The angle m∠AFE is 128 degrees.
<h3>How to find angles?</h3>
∠AFB ≅ ∠EFD
∠EFD = 5x + 6
m∠DFC = (19x - 15)°
m∠EFC = (17x + 19)°
m∠AFE = ?
m∠AFB + m ∠EFD + m∠AFE = 180
Therefore,
5x + 6 + 5x + 6 + m∠AFE = 180
5x + 5x + 6 + 6 + m∠AFE = 180
10x + 12 + m∠AFE = 180
10x + m∠AFE = 180 - 12
10x + m∠AFE = 168
m∠AFE = 168 - 10x
m∠EFC = m ∠EFD + m∠DFC
17x + 19 = 5x + 6 + 19x - 15
17x - 5x - 19x = 6 - 15 - 19
-7x = - 28
x = 28 / 7
x = 4
Therefore,
m∠AFE = 168 - 10x
m∠AFE = 168 - 10(4)
m∠AFE = 168 - 40
m∠AFE = 128°
Therefore, the angle m∠AFE = 128°
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Answer:
The area of the rectangle plus the area of the triangle under the line.
Step-by-step explanation:
Answer:
d
Step-by-step explanation:
Quadrant 3 will have a negative x and a negative y........so ur answers are :
A and C
Answer:
x² - 10x + 29
Step-by-step explanation:
The standard form of a quadratic is , ax² + bx + c (a ≠ 0 )
Given
(x - 5)² + 4 ← expand factor using FOIL
= x² - 10x + 25 + 4
= x² - 10x + 29 ← in standard form
