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Debora [2.8K]
3 years ago
15

Find the equation of the line shown

Mathematics
2 answers:
Delvig [45]3 years ago
3 0
Y = x + 6 is the correct answer
Lady_Fox [76]3 years ago
3 0

Answer:

Y + x +6is correct answer

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x=26/3 because you need to comine like terms as usual

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Graph the inequality;y&gt;-5x+3
Evgesh-ka [11]
Start your dot on 3 on the y axis. Move is downwards on the y axis by 5 everytime you move over once on the x axis. Shade all the stuff above the line since it says y is greater than -5x+3
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Which graph represents y = –2x?
Andrei [34K]

Solution:

<u>In this case, we are given:</u>

  • Equation: y = -2x
  • Slope = -2
  • y-intercept = 0

Looking at Option A, we can tell that its <u>slope is -2 and y-intercept is 0.</u>

Since this is matching with the info we are given, Option A is correct.

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2 years ago
Between what two numbers would 9 be located on a number line?
Mariulka [41]

it \: is \: simple \\ between \: 8 \:  \:  \: 10

5 0
3 years ago
Read 2 more answers
Use the factors of the function and the y-intercept to find the standard form of the equation representing Jared’s function. Typ
Georgia [21]

The y-intercept of a function is the point where the graph crosses the \mathbf{y = x^3 + 2x^2 - 193x - 270 }

  • The factors of the Jared's graph are: (x - 10), (x + 3) and (x + 9)
  • The y-intercept is -13.5
  • The standard equation of the function is: \mathbf{y = x^3 + 2x^2 - 193x - 270 }

<u>(a) The factors</u>

First, we write out the points where the function cross the x-axis.

The points are:

\mathbf{x = 10}

\mathbf{x = -3}

\mathbf{x = -9}

Equate the above points to 0

\mathbf{x -10 = 0}

\mathbf{x +3 = 0}

\mathbf{x +9 = 0}

Hence, the factors are: (x - 10), (x + 3) and (x + 9)

<u>(b) The y-intercept</u>

This is the point where the graph crosses the y-axis.

From the attached graph, the graph crosses the y-axis at -13.5.

Hence, the y-intercept is -13.5

<u>(c) The standard form</u>

In (a), we have:

\mathbf{x -10 = 0}

\mathbf{x +3 = 0}

\mathbf{x +9 = 0}

Multiply the above equations

\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 \times 0 \times 0}

\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 }

Expand

\mathbf{(x - 10) \times (x^2 + 3x + 9x + 27) = 0 }

\mathbf{(x - 10) \times (x^2 + 12x + 27) = 0 }

Expand

\mathbf{x^3 + 12x^2 + 27x - 10x^2 - 220x - 270 = 0 }

Collect like terms

\mathbf{x^3 + 12x^2 - 10x^2+ 27x  - 220x - 270 = 0 }

\mathbf{x^3 + 2x^2 - 193x - 270 = 0 }

Replace 0 with y

\mathbf{y = x^3 + 2x^2 - 193x - 270 }

Hence, the standard form is: \mathbf{y = x^3 + 2x^2 - 193x - 270 }

Read more about graphs and functions at:

brainly.com/question/18806107

3 0
2 years ago
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