Given the polynomial function
If (x-3) is a factor of P(x), then
, for some polynomial Q of 1st degree,
Then according to the factor theorem P(3)=0, because P(3)=(3-3)Q(x)=0*Q(3)=0.
Check
≠0
we see that P(3) is not 0, so (x-3) is not a factor of P(x).
Answer: no
Answer:
62.80
Step-by-step explanation:
I hope this helped you out!!
Answer:
9x3=27
Step-by-step explanation:
when we break the question down, we can see that the height of the prism is 9 and the width is 3 all we have to do is multiply 9 by 3 to get out answer of 27
Answer:
2 cups of flour
Step-by-step explanation:
If you have 2 and 2/3 cups milk for every cup of flour then 4 and 1/3 is 2 2/3 times two so 1 cup of flour times 2 is 2 cups of flour.
Answer:
x³ + x² − 4x + 6 = 0
Step-by-step explanation:
Imaginary roots come in conjugate pairs. So if 1+i is a root, then 1−i is also a root.
(x − (-3)) (x − (1+i) (x − (1−i)) = 0
(x + 3) (x² − (1+i) x − (1−i) x + (1+i) (1−i)) = 0
(x + 3) (x² − x − ix − x + ix + 1 − i²) = 0
(x + 3) (x² − 2x + 2) = 0
x (x² − 2x + 2) + 3 (x² − 2x + 2) = 0
x³ − 2x² + 2x + 3x² − 6x + 6 = 0
x³ + x² − 4x + 6 = 0
