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3 years ago

The Pythagorean theorem states that a² + b² = c² for a right triangle with leg lengths, a and b, and hypotenuse length, c.

Mathematics

1 answer:

Jet001 [13]3 years ago

6 0

Answer:

Step-by-step explanation:

Draw the third point at (0, 0). This would make the distance from (3,0) to (0,0) equal to 3, and the distance from (0,4) to (0,0) be 4.

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Firdavs [7]

(75-5)x1+4
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A candy company can make 350 pounds of chocolate and 6 hours how much can they make in 10 hours

Andrew [12]

350 ÷ 6 = 58.33

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58.33 × 10 = 583.3

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What is 5+7?<br><br> I literally will give the highest amount of points

Dovator [93]

5 + 7 is equal to 12. Is this kindergarten math?

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3 years ago

Let P be between M and N use the segment addition postulate to solve for X

marta [7]

Step-by-step explanation:

given,

MP = x - 8

PN = 3x - 9

MN = 21

we know,

according to segment addition postulate AB + BC = AC

now,

MP + PN = MN

→ x - 8 + 3x - 9 = 21

→ 4x - 17 = 21

→ 4x = 21 + 17

→ 4x = 38

→ x = 38/4 = 9

→ x = 9

therefore, value of x is 9.

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3 years ago

In this diagram, BAC~ EDF. if the area of BAC = 6 in, what is the area of EDF.

gulaghasi [49]

Answer:

2.7 square inch

Step-by-step explanation:

$\triangle BAC \sim \triangle EDF... (Given) \\$

$\therefore$ By area of similar triangle theorem:

$\frac{A(\triangle BAC)}{A(\triangle EDF)} = \frac{BC^2}{EF^2} \\\\\therefore \frac{6}{A(\triangle EDF)} = \frac{3^2}{2^2} \\\\\therefore \frac{6}{A(\triangle EDF)} = \frac{9}{4} \\\\\therefore A(\triangle EDF) = \frac{4\times 6}{9} \\\\\therefore A(\triangle EDF) = \frac{24}{9} \\\\\therefore A(\triangle EDF) = 2.6667\\\\\huge \purple {\boxed {\therefore A(\triangle EDF) = 2.7\: in^2}}$

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4 years ago