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Fofino [41]
3 years ago
9

A wire 23 cm long is cut into two pieces. The longer piece is 7 cm longer than the shorter piece.

Mathematics
1 answer:
Flura [38]3 years ago
7 0

Length of a wire = 23 cm

Given that :

▪︎The wire was cut into two pieces.

▪︎The longer piece of wire is 7 cm longer than the shorter piece of wire.

Let the shorter piece of wire be x.

Then, the longer piece of wire = x+7

An equation that can be derived from these statements :

▪︎x + x + 7 = 23

Let us solve this equation :

= \tt x  + x +7  = 23

= \tt 2x + 7 = 23

= \tt 2x = 16

= \tt x =  \frac{16}{2}

\color{plum} \hookrightarrow  \color{plum}x = 8

Thus, the value of x = 8.

Which means :

Length of the shorter piece of wire = 8 cm

Length of the longer piece of wire = 8 + 7 = 15 cm

Since the length of the two wires add up to form 23 cm(8+15=23), we can conclude that we have found out the correct measures of each wire.

Therefore, the length of the shorter piece of wire = <u>8 cm</u>

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∑ 8(\frac{7}{3})⁽ⁿ⁻¹⁾ from n = 1 to n = 5

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n = 2 → 8(\frac{7}{3})⁽²⁻¹⁾

         = \frac{56}{3}                                         = \frac{1512}{81}    

n = 3 → 8(\frac{7}{3})⁽³⁻¹⁾

          = \frac{392}{9}                                     = \frac{3528}{81}

n = 4 → 8(\frac{7}{3})⁽⁴⁻¹⁾

          = \frac{2744}{27}                                 = \frac{8232}{81}

n = 5 → 8(\frac{7}{3})⁽⁵⁻¹⁾

          = \frac{19208}{81}                                = \frac{19208}{81}

                                                                            Sum = \frac{33128}{81}

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