Answer:
domain: 2x+1 not equal to zero, then x not equal to -1/2
Set 2x+1>0
then x>-1/2
100^(3-4x)/(2x+1)<=0.01^(5x-8)/(2x+1)
100^(3-4x)<=0.01^(5x-8)
(10^2)^(3-4x)<=[10^(-2)]^(5x-8)
10^[2*(3-4x)]<=10^[(-2)*(5x-8)]
10^(6-8x)<=10^(16-10x)
6-8x<=16-10x
2x<=10
x<=5
combine x>-1/2 and x<=5
then - 1/2<x<=5
Set 2x+1<0
then x<-1/2
100^(3-4x)/(2x+1)<=0.01^(5x-8)/(2x+1)
100^(3-4x)>=0.01^(5x-8)
(10^2)^(3-4x)>=[10^(-2)]^(5x-8)
10^[2*(3-4x)]>=10^[(-2)*(5x-8)]
10^(6-8x)>=10^(16-10x)
6-8x>=16-10x
2x>=10
x>=5
combine x<-1/2 and x>=5
, then x does not exist while 2x+1<0
so answer is - 1/2<x<=5
Answer:
1.55
Step-by-step explanation:
Answer:187 questions answered correctly
Step-by-step explanation:
4*48=192
192-5=187
Ok
so the focus is on the opening side of the parabola
so for a vertex of (h,k)
opening up and down
(x-h)²=4p(y-k)
p is the distance from vertex to focus
it is also the distance from the vertex to the closes point on directix
2p=distance from focus to directix
p is positive if the focus is above the directix
ok
y=9 and (7,6)
9>6
directix is above the vertex
p is negative
find distance
from 9 to 6 is 3
3=2p
1.5=p
p is negative
and the vertex will be 1.5 above the focus and 1.5 below the directix
vertex is (7,7.5)
(x-7)²=4(-1.5)(y-7.5) is de equation
GX, FW, and YH. That should be the main ones.
