if a > 0, there are two possible solutions:
the square root of a square is the base in absolute value bars
if a = 0, that means x = 0. anything multiplied by 0 is 0
if a < 0, there are no solutions because anything squared has to be positive
Answer:
y = e^x
Step-by-step explanation:
That curve represents a typical function of y = e^x, and to decide if it is y = e^x or y = e^x + 1 you need to replace x = 0
y = e^(0) = 1
y = e^(0) + 1 = 2
If you see the graph when x = 0, y = 1
So it is y = e^x
Answer:
p^3 / q^12
Step-by-step explanation:
p^6 q^4
------------------
p^3 q^16
We know a^b / a^c = a^(b-c)
First with variable p
p^6 / p ^3 = p^(6-3) = p^3
Then with variable q
q^4 / q^16 = q^(4-16) = q^-12 and a^-b = 1/ a^b = 1 /q^12
p^3 * 1/ q^12
p^3 / q^12
Answer:
m=5
Step-by-step explanation:
c=30m+50
c=20m+100
substitute
20m+100=30m+50
like terms
100-50=30m-20m
50=10m
m=5
