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balandron [24]
2 years ago
14

HELP I NEED HELP ASAP

Mathematics
1 answer:
Anni [7]2 years ago
7 0
I think the answer is letter D.

:) have a good day
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Find the residual values, and use the graphing calculator tool to make a residual plot. A 4-column table with 5 rows. The first
Georgia [21]

Answer:

Solution-

We know that,

Residual value = Given value - Predicted value

The table for residual values is shown below,

Plotting a graph, by taking the residual values on ordinate and values of given x on abscissa, a random pattern is obtained where the points are evenly distributed about x-axis.

We know that,

If the points in a residual plot are randomly dispersed around the horizontal or x-axis, a linear regression model is appropriate for the data. Otherwise, a non-linear model is more appropriate.

As, in this case the points are distributed randomly around x-axis, so the residual plot show that the line of regression is best fit for the data set.

Hope this helps!

Step-by-step explanation:

4 1
3 years ago
Read 2 more answers
What is required of a proportional relationship that is not required of a general linear relationship?
Lana71 [14]
The proportional relationship should require they y-intercept and is then 0 and the linear relationship should be in a straight line to be a linear! Hope this helps!
8 0
3 years ago
Someone help me ( view picture below )
oksano4ka [1.4K]

Answer:

D. 13

Step-by-step explanation:

x = 5

2 x 5 + 3 = 13

5 + 8 = 13

meaning the side length has to be 13, also.

5 0
3 years ago
Write the equation of the parabola in vertex form.
givi [52]

Answer: -9 = a(1 - 3)² + 3

Step-by-step explanation:

Vertex Form Equation:

y = a(x - h)² + k

vertex: (h, k) which means

h = 3

k = 3

because your vertex is (3, 3).

Your point is (1, -9) which is (x, y).

This means

x = 1

y = -9

Now, plug everything into your Vertex Form Equation:

-9 = a(1 - 3)² + 3

That’s your equation and final answer, but of course, if you need to, you can solve for a if you need to.

If a is positive, the parabola opens up. If a is negative, the parabola opens down.

Hope this helps!

3 0
3 years ago
How do i solve 3x² - 8x + 2 = 0 using quadratic formula?
DENIUS [597]
3x^2 - 8x + 2 = 0\\ \\a=3 , \ \ b=-8 , \ \ c=2 \\ \\x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a} =\frac{8-\sqrt{ (-8)^2-4 \cdot 3\cdot 2}}{2 \cdot 3} =\frac{8-\sqrt{ 64-24 }}{6} =\\ \\ =\frac{8-\sqrt{40 }}{6} = \frac{ 8-\sqrt{4\cdot 10 } }{6} = \frac{ 8-2\sqrt{ 10 }}{6} = \frac{2 (4-\sqrt{ 10 })}{6} = \frac{ 4-\sqrt{ 10 } }{3}

x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a} =\frac{8+\sqrt{ (-8)^2-4 \cdot 3\cdot 2}}{2 \cdot 3} = \frac{ 4+\sqrt{ 10 } }{3}



7 0
3 years ago
Read 2 more answers
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