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natulia [17]
3 years ago
8

A bag contains 4 orange marbles, 2 yellow marbles, and 9 red marbles. Which of the following best describes the probability of c

hoosing a red marble from the bag?
Likely

As likely as not

Unlikely

Impossible
Mathematics
2 answers:
Lesechka [4]3 years ago
8 0

Answer:

very likely

Step-by-step explanation:

Most of the marbles in the bag are red so that's why it's likely.

polet [3.4K]3 years ago
8 0

Answer: The answer would be likely

Step-by-step explanation:

You might be interested in
Find the area of each figure. round to the hundredths place when necessary
notsponge [240]

Answer:

115.48m^{2}

Step-by-step explanation:

This shape can be split into two distinct shapes

Two halves of a semi circle, and a rectangle in between

Circle:

Putting both halves of the semi circle together will give you a full circle. The diameter of the circle is given (7m).

The area of a circle is A = π r^{2}

The radius, r, is half of the diameter, so 7 / 2 = 3.5m

A = π r^{2}

A = π * 3.5^{2}

A = 38.38m^{2}

Rectangle:

The area of a rectangle is A = h b

The height, h, is known at 7m

The base, b, can be found by removing the length from the dot to the end of the semi circles. This length is the radius of the semi circles, 3.5m

Removing the radius from the total length given

18 - 3.5 - 3.5 = 11m

The base is 11m

A = h b

A = 7 * 11 = 77m^{2}

Total Area = Circle area + Rectangle area

Total Area = 38.38 + 77 = 115.48m^{2}

6 0
3 years ago
Is there an.expert answerer who can help me with this
nlexa [21]
I think the answer is 2,612.48 because if you multiply the radius, 80 by itself you get 640. Then if you multiply 640 by 3.14 and then multiply the product by 1.3 you get 2,612.48.
4 0
4 years ago
NEED HELP NOWW!!! Andre is in charge of cooking broccoli and zucchini for a large group. He has to spend all $17 he has and can
Nookie1986 [14]

Answer:

a. 9 pounds of broccoli and 1 pound of zucchini

b. 7lbs broccoli and 2 lbs of zucchini

c. 6lbs zucchini and 4lbs broccoli.

Step-by-step explanation:

a. well just come up with 2 numbers that equal up to 10 so yea.

b. 7lbs broccoli 2 lbs of zucchini - this is 9 lbs of veggies but it costs 17 dollars because (7*2)+(2*1.50)=17

14+3=17 (the 7 and 2 is the amount of pounds of veggies and the 2 and 1.50 are the prices)

c. it would be 6 lbs of zucchini and 4 lbs of broccoli because 6+4=10 and (6*1.50)+(4*2)=17

7 0
3 years ago
Read 2 more answers
4. The value of y varies directly with x. When y = 275, x = -22 What is y when x = 17.5?​
Helga [31]

y = x

275 = -22

y = 17.5

y = (17.5*275)/-22

y = -179.0

5 0
3 years ago
The reading speed of sixth-grade students is approximately normal, with a mean speed of 125 words per minute and a standard devi
Lisa [10]

Answer:

<u>Part A</u>

<u>μ of the reading speed of sixth-grade students = 125 words</u>

<u>σ of the reading speed of sixth-grade students = 24 words</u>

<u>Part B</u>

<u>The probability that a randomly selected sixth-grade student reads less than 100 words per minute is 14.92%</u>

<u>Part C</u>

<u>The probability that a randomly selected sixth-grade student reads more than 140 words per minute is 26.43% </u>

Step-by-step explanation:

Part A:

μ of the reading speed of sixth-grade students = 125 words

σ of the reading speed of sixth-grade students = 24 words

Part B:

1. Let's find the z-score for a randomly selected sixth-grade student that reads less than 100 words per minute:

z-score = (100 - 125)/24

z-score = -25/24

z-score = -1.04

2. Now, let's find out the probability that a randomly selected sixth-grade student that reads less than 100 words per minute, using the z-table:

P (-1.04) = 0.1492

<u>This means that the probability that a randomly selected sixth-grade student that reads less than 100 words per minute is 14.92%</u>

Part C.

1. Let's find the z-score for a randomly selected sixth-grade student that reads more than 140 words per minute:

z-score = (140 - 125)/24

z-score = 15/24

z-score = 0.63

2. Now, let's find out the probability that a randomly selected sixth-grade student that reads more than 140 words per minute, using the z-table:

P (0.63) = 0.7357

But we're being asked for a randomly selected student that reads more than 140 words, then:

1 - P(0.63) = 1 - 0.7357 = 0.2643

<u>This means that the probability that a randomly selected sixth-grade student that reads more than 140 words per minute is 26.43%</u>

8 0
4 years ago
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