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3 years ago

Please help! What is 10-9+8?

Mathematics

2 answers:

kari74 [83]3 years ago

7 0

Your answer is 9. 10-9=1 and 1+8=9.

SVEN [57.7K]3 years ago

4 0

10 minus 9 would be 1 and 1 plus 8 is 9 so your answer is 9!!!

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5a + 18 < −27 pre algibra

Grace [21]

Answer:

X < -9

Step-by-step explanation:

5a +18 < -27

5a < -27 -18

5a < - 45

5a/5 < - 45/5

a < - 9

Answred by Gauthmath

5 0

3 years ago

Read 2 more answers

Using the quadratic formula to solve 4x2 – 3x + 9 = 2x + 1, what are the values of x?

yaroslaw [1]

Answer:

The value of x is:

$x=\dfrac{5\pm \sqrt{103}i}{8}$

Step-by-step explanation:

we have to use the quadratic formula to solve for x.

The equation is given as:

$4x^2-3x+9=2x+1$

which could also be written as:

$4x^2-3x+9-2x-1=0\\\\4x^2-3x-2x+9-1=0\\\\\\4x^2-5x+8=0$

The quadratic formula for the quadratic equation of the type:

$ax^2+bx+c=0$ is given as:

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here we have:

a=4, b=-5 and c=8.

Hence, by the quadratic formula we have:

$x=\dfrac{-(-5)\pm \sqrt{(-5)^2-4\times 8\times 4}}{2\times 4}\\\\x=\dfrac{5\pm \sqrt{25-128}}{8}\\\\\\x=\dfrac{5\pm \sqrt{103}i}{8}$

Hence, the value of x is:

$x=\dfrac{5\pm \sqrt{103}i}{8}$

8 0

3 years ago

Read 2 more answers

You borrowed $59,000 for 2 years at 11% which was compounded annually. What

gayaneshka [121]

Answer:

$72693.9

Step-by-step explanation:

To get this answer you need to use the compound interest formula, which will be A=P(1+r/n)^n(t). P=59,000 r=11%=0.11 n=1 (annually) t=2 years. From there you should be able to figure the rest out and get the answer. Hope this helps!

6 0

2 years ago

Take LCM ald then do in full processplease help me

Marina86 [1]

Answer:a) L.C.M OF 2,3,5 is 30

THEREFORE=60/30+15/30÷10/30-6/30

=60/30+15/30×30/10-6/30(DMAS)

=60/30+3/2-6/30

=60+45/30 -6/30(ADDITION FIRST THEN SUBTRACTION.

=105/30-6/30

=105-6/30

=99/30

=33/10

b)(3+1/2)÷(2-1/2)=L.C.M IS 2,=(6+1/2)÷(4-1/2)=7/2÷3/2=7/3

8 0

3 years ago

Mr eliot is extremely careful with his money. He recently invested part of his $150,000 life savings in gold bullion and the res

DIA [1.3K]

Answer:

The amount invested in gold bullion by Mr. Eliot = $50,000

Step-by-step explanation:

Total amount of savings Me. Eliot ha s = $150,000

Let us assume the amount invested in gold bullion = $m

So, the amount invested in bank = $150,000 - m

Now, 5% on m = $\frac{5}{100} \times m = 0.05 m$

So, the profit in gold bullion = 0.05 m

and 3% on (150,000 -m) = $\frac{3}{100} \times (150,000 -m) = 0.03 (150,000 -m)$

= 4,500 - 0.03 m

So, the profit in bank = 4,500 - 0.03 m

Now, the total profit = $5,500

⇒Profit from gold bullion + ban = $5,500

⇒0.05 m + 4,500 - 0.03 m = $5,500

or, 0.02 m = 1000

⇒ m = 1000/0.02 = 50,000

Hence, the amount invested in gold bullion = m = $50,000

3 0

3 years ago