The unit rate is $2.20 for each pencil because 11 divided by 5 is 2.2
Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
Find out more solving for distance at brainly.com/question/10739348
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Answer:
Step-by-step explanation:
1. List out all data from least to greatest
2. Find the median (the middle number)
3. Find the median of the lower part of data (the numbers lesser in value compared to the median; do not include the median while finding this)
4. Do the same with the numbers above the median.
5. Take the medians of the lower numbers and higher and find the difference,
6. Thats your interquartile range
Answer:
Yes
Step-by-step explanation:
I hope I helped you^_^
