Answer:
![y = 2](https://tex.z-dn.net/?f=y%20%3D%202)
Step-by-step explanation:
1) Divide both sides by 2.
![3y - 6 = 0](https://tex.z-dn.net/?f=3y%20-%206%20%3D%200)
2) Add 6 to both sides.
![3y = 6](https://tex.z-dn.net/?f=3y%20%3D%206)
3) Divide both sides by 3.
![y = \frac{6}{3}](https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B6%7D%7B3%7D%20)
4) Simplify 6/3 to 2.
![y = 2](https://tex.z-dn.net/?f=y%20%3D%202)
<em><u>Therefor</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>y</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>2</u></em><em><u>.</u></em>
Answer:
f'(x)= ![\frac{1}{\sqrt{1-x^{2} } }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%7B1-x%5E%7B2%7D%20%7D%20%7D)
Step-by-step explanation:
As khown the derivative of arcsin(x) is;
f'(x)= ![\frac{1}{\sqrt{1-x^{2} } }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%7B1-x%5E%7B2%7D%20%7D%20%7D)
Answer:
129 square foot
Step-by-step explanation:
<u>Step 1: Convert height of the door to inches</u>
Height of the door = 10 feet 8 inches
1 feet = 12 inches
10 feet = y inches
<em>Cross Multiply</em>
y = 120 inches
Height of door in inches = 120 + 8 =128 inches
<u>Step 2: Find the surface area of one side of the door</u>
Surface area = length x width
length = 128 inches
width = 145 inches
Surface area = 128 x 145
Surface area = 18560 inches
<u>Step 3: Convert surface area from inches to square foot</u>
Surface area = 18560 inches
1 square foot = 144 inches
y = 18560 inches
<em>Cross multiply</em>
144y = 18560
y = 18560/144
y = 128.89 rounded off to 129 square foot.
Therefore, you should report 129 square foot surface area to the hardware store.
!!
Answer: its 4 miles per hour
Step-by-step explanation: we divide but that not all u do........
First, we have to identify the right triangle formed
As you can observe, segment AB is divided into two equal parts. We can find one part of AB using the Pythagorean's Theorem
![c^2=a^2+b^2](https://tex.z-dn.net/?f=c%5E2%3Da%5E2%2Bb%5E2)
Where c = 15 and b = 12. Let's find a
![\begin{gathered} 15^2=a^2+12^2 \\ 225=a^2+144 \\ 225-144=a^2 \\ a=\sqrt[]{81} \\ a=9 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%2015%5E2%3Da%5E2%2B12%5E2%20%5C%5C%20225%3Da%5E2%2B144%20%5C%5C%20225-144%3Da%5E2%20%5C%5C%20a%3D%5Csqrt%5B%5D%7B81%7D%20%5C%5C%20a%3D9%20%5Cend%7Bgathered%7D)
Then, we know that AB = 2a, so
![AB=2\cdot a=2\cdot9=18ft](https://tex.z-dn.net/?f=AB%3D2%5Ccdot%20a%3D2%5Ccdot9%3D18ft)
<h2>Hence, AB is 18 feet long.</h2>