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2 years ago

What is the perimeter and area of this shape:

Mathematics

1 answer:

o-na [289]2 years ago

5 0

Perimeter = 10.28
Area = 7.14

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Rate (R) = 25/3<br>Interest = Rs. 350<br>(d) Principal = Rs. 2400<br><br>Find the time (t)

julia-pushkina [17]

Answer:

The value of t is 1.75 years.

Step-by-step explanation:

Given that simple interest formula is I = (P×R×T)/100. So you have to substitute the following values into the formula :

$i = \frac{prt}{100}$

$let \: i = 350,p = 2400,r = \frac{25}{3}$

$350 = \frac{2400 \times \frac{25}{3} \times t }{100}$

$350 = \frac{20000t}{100}$

$350 \times 100 = 20000t$

$20000t = 35000$

$t = 35000 \div 20000$

$t = 35 \div 20$

$t = 1.75 \: years$

8 0

3 years ago

(4.8x10x7) + 6,500,000 what is the value of the expression

Fiesta28 [93]

Answer:

=(48*7) +65*10^5

=((40+8) *7) +65*10^5

=(280+56)+65*10^5

=336+65*10^5

=.336*10^3+65*10^5

=.00336*10^5+65*10^5

=(.00336+65) *10^5

=64.00336*10^5

4 0

3 years ago

The radius of a cone is increasing at a constant rate of 7 meters per minute, and the volume is decreasing at a rate of 236 cubi

storchak [24]

Answer:

The rate of change of the height is 0.021 meters per minute

Step-by-step explanation:

From the formula

$V = \frac{1}{3}\pi r^{2}h$

Differentiate the equation with respect to time t, such that

$\frac{d}{dt} (V) = \frac{d}{dt} (\frac{1}{3}\pi r^{2}h)$

$\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (r^{2}h)$

To differentiate the product,

Let r² = u, so that

$\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (uh)$

Then, using product rule

$\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h\frac{du}{dt}]$

Since $u = r^{2}$

Then, $\frac{du}{dr} = 2r$

Using the Chain's rule

$\frac{du}{dt} = \frac{du}{dr} \times \frac{dr}{dt}$

∴ $\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h(\frac{du}{dr} \times \frac{dr}{dt})]$

Then,

$\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]$

Now,

From the question

$\frac{dr}{dt} = 7 m/min$

$\frac{dV}{dt} = 236 m^{3}/min$

At the instant when $r = 99 m$

and $V = 180 m^{3}$

We will determine the value of h, using

$V = \frac{1}{3}\pi r^{2}h$

$180 = \frac{1}{3}\pi (99)^{2}h$

$180 \times 3 = 9801\pi h$

$h =\frac{540}{9801\pi }$

$h =\frac{20}{363\pi }$

Now, Putting the parameters into the equation

$\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]$

$236 = \frac{1}{3}\pi [(99)^{2} \frac{dh}{dt} + (\frac{20}{363\pi }) (2(99)) (7)]$

$236 \times 3 = \pi [9801 \frac{dh}{dt} + (\frac{20}{363\pi }) 1386]$

$708 = 9801\pi \frac{dh}{dt} + \frac{27720}{363}$

$708 = 30790.75 \frac{dh}{dt} + 76.36$

$708 - 76.36 = 30790.75\frac{dh}{dt}$

$631.64 = 30790.75\frac{dh}{dt}$

$\frac{dh}{dt}= \frac{631.64}{30790.75}$

$\frac{dh}{dt} = 0.021 m/min$

Hence, the rate of change of the height is 0.021 meters per minute.

3 0

2 years ago

What is the mean of 5,5, 8,10

TiliK225 [7]

So, when doing this kind of problems, the first thing that we would want to do is to add up (all) the numbers first, and by doing this, it would look like the following:

$5+5+ 8+10=28$

Then, we would then divide it by how many numbers they are.

$\boxed{28\div4} \ =7$

Your answer: 7

7 0

2 years ago

Read 2 more answers

A circle with radius 142.5 has an arc with a 24 degree angle. What is the length of the arc?

MissTica

Answer: 59.690260418206

The result is approximate. Round that value however you need to.

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Explanation:

For a circle with radius r = 142.5, the full distance around the edge (aka perimeter aka circumference) is found by using the formula below.

C = 2*pi*r

C = 2*pi*142.5

C = 895.353906273091

That value is approximate. I used my calculator's stored value of pi to get the most accuracy possible.

That value of roughly 895 represents the distance around a full circle of that radius, but we only want a 24 degree pizza slice.

In other words, we want 24/360 = 1/15 of the full perimeter

(1/15)*895.353906273091 = 59.690260418206

5 0

2 years ago

Read 2 more answers