Problem 1: Evaluate<span> the summation of 3 times negative 2 to the n minus 1 power, ... The one I just posted looks like this: \sum_{</span>n=1}^{12<span>} </span>2n+5<span>.</span>
Everything is divisible by five, so pull out five
5(-k^2+4k-6)
5 is the mean of variable a I might be wrong
Answer:
Step-by-step explanation:
