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3 years ago

Factor the gcf -5k^2+20k-30

Mathematics

1 answer:

Degger [83]3 years ago

8 0

Everything is divisible by five, so pull out five

5(-k^2+4k-6)

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30000mm how much did it grow in a meter

Serggg [28]

30000mm÷10=3000cm
3000cm÷100=30m
Answer: 30m

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3 years ago

Darrell has the following data:

aleksley [76]

Answer:

I'm fairly certain that c=10. Don't quote me on that.

Step-by-step explanation:

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2 years ago

A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra

Harman [31]

Answer:

A.

The student made an error in step 3 because a is positive in Quadrant IV; therefore,

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

Step-by-step explanation:

Given

$P\ (a,b)$

$r = \± \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}$

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

$r = \sqrt{(a)^2 + (b)^2}$

Since a belongs to the x axis and b belongs to the y axis;

$cos\theta$ is calculated as thus

$cos\theta = \frac{a}{r}$

Substitute $r = \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}$

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}}$

Rationalize the denominator

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}$

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

So, from the list of given options;

The student's mistake is that a is positive in quadrant iv and his error is in step 3

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3 years ago

Andre ran 1/2 of a mile in 1/15 of an hour.

Oduvanchick [21]

1/30 wish you well on your assignment ~JyMarkus

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2 years ago

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Which expression shows the result of applying the distributive property to −2(13x−15)−2(13x−15) ?

defon

D is the answer good luck

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3 years ago

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