[10 points] [ASAP]
1 answer:
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Answer:
A)196J
B)-208J
C)3467J
Step-by-step explanation:
We are given that a 20 kg cylindrical mass is dropped onto the mat from a height of 1 m above the mat. During the impact, the cylinder’s vertical velocity reaches zero at the instant the mat has compressed to only 4 cm thick.
So, The Mat gets compressed by : 10cm - 4 cm = 6 cm=0.06 m
a)
Using Conservations of energy
Potential energy at the top = Kinetic energy at the point before touching the surface
Kinetic energy = mgh=
b)
Work done by the mat do to stop the fall of the cylinder =
C)
Work done=
F=3467J
