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Alex787 [66]
3 years ago
13

What Is The Highest Common Factor in 160 and 4800​

Mathematics
1 answer:
Mariana [72]3 years ago
5 0

Answer: the greast common factor between the two is 160

Step-by-step explanation: Find the prime factorization of 160

160 = 2 × 2 × 2 × 2 × 2 × 5

Find the prime factorization of 4800

4800 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 5 × 5

To find the GCF, multiply all the prime factors common to both numbers:

Therefore, GCF = 2 × 2 × 2 × 2 × 2 × 5

Hope this helps and thanks again for helping me :)

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Help please ........
Licemer1 [7]

The answer would be A) 2,640.

In order to find this we must first find an amount of people per square feet. Since we are given that 10 people fit in a 5x5 square, we know that 10 people fit in 25 square feet. This will be the basis for our final calculation.

Now we need to find how many square feet we have. Since it is a quarter of a mile long, we'll divide the number of feet in a mile by 4.

5,280/4 = 1320.

Now we take the length and multiply it by the width, which is 5ft.

1320 * 5 = 6,600 square feet.

So we now know the size of the crowd. We can use that and multiply it by the factor that we found at the start to find the number of people.

6,600 square feet * 10 people/ 25 square feet = 2,640 people.

8 0
4 years ago
Andrew must spend less than 53$ on meals during the weekend. he has already spent 21$ on meals costing 8$ average. how many addi
Shkiper50 [21]

Andrew can buy maximum 3 meals this weekend.

From given question,

Andrew must spend less than 53$ on meals during the weekend.

He has already spent 21$ on meals costing 8$ average.

Let x, the number of meals

So, we get an inequality,

8x + 21 < 53

We need to find the number of meals he can buy this weekend.

From above inequality,

⇒ 8x + 21 < 53

⇒ 8x < 53 - 21

⇒ 8x < 32

⇒ x < 4

This means, from 1 to 3 meals.

Therefore, Andrew can buy maximum 3 meals this weekend.

Learn more about an inequality here:

brainly.com/question/19003099

#SPJ4

3 0
1 year ago
Louise begins factoring the polynomial, which has four terms.
ad-work [718]

Louise wants to factorize completely the given polynomial 4x^{3}+12x^{2}+5x+15

Grouping first, second terms together and third, fourth terms together

= 4x^{3}+12x^{2}+5x+15

Taking 4x^{2} common from first and second terms of the given expression and taking 5 common from the third and fourth terms.

==4x^{2}(x+3)+5(x+3)

Taking (x+3) common from the given expression,

==(4x^{2}+5)(x+3) is the completely factored form.

5 0
3 years ago
Solve for x: -1/2(-4+2x) = -6 - 4x
antiseptic1488 [7]
-\dfrac{1}{2}(-4+2x)=-6-4x\ \ \ \ \ |multiply\ both\ sides\ by\ (-2)\\\\-4+2x=12+8x\ \ \ \ |add\ 4\ to\ both\ sides\\\\2x=16+8x\ \ \ \ \ |subtract\ 8x\ from\ both\ sides\\\\-6x=16\ \ \ \ \ |divide\ both\ sides\ by\ (-6)\\\\x=-\dfrac{16}{6}\\\\x=-\dfrac{8}{3}\\\\\boxed{x=-2\frac{2}{3}}
5 0
3 years ago
Look at pic I need help!!!! :(
Novosadov [1.4K]

Answer: x=12

Step-by-step explanation:

5x-15=2x+21(AIA)

3x-15=21

3x=36

x=12

7 0
3 years ago
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