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2 years ago

PLEASE HELP !! ILL GIVE 40 POINTS ; PLUS BRAINLIEST !! DONT SKIP ANSWER.

Mathematics

2 answers:

Wewaii [24]2 years ago

6 0

B??? I’m so srry if I’m wrong but try

bearhunter [10]2 years ago

5 0

Answer:

its c. POQ and KLJ

Step-by-step explanation:

it just is

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The length of ZX is 2 units. What is the perimeter of triangle XYZ?

dezoksy [38]

Keywords

triangle,perimeter,distance, length, side, points

we know that

The perimeter of a triangle is the sum of the three length side

To find the length side calculate the distance between two points

The formula to calculate the distance between to points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step 1

Find the distance ZY

$Z(1,0)\\Y(3,1)$

substitute the values

$d=\sqrt{(1-0)^{2}+(3-1)^{2}}$

$dZY=\sqrt{5}\ units$

Step 2

Find the distance XY

$X(-1,4)\\Y(3,1)$

substitute the values

$d=\sqrt{(1-4)^{2}+(3+1)^{2}}$

$dXY=\sqrt{25}=5\ units$

Step 3

Find the perimeter of the triangle

$P=ZX+ZY+XY$

we have

$dZX=2\sqrt{5}\ units$

$dZY=\sqrt{5}\ units$

$dXY=5\ units$

Substitute

$P=(2\sqrt{5}+\sqrt{5}+5)\ units$

therefore

the answer is

$P=(3\sqrt{5}+5)\ units$

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2 years ago

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A student solved this problem by working backward.

marusya05 [52]

She has 38 balloons altogether

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3 years ago

Determine the exact value of sin 30° tan 45° + tan 30° sin 60⁰

solong [7]

Answer:

Step-by-step explanation:

1) if sin30=0.5; tan45=1; tan30=1/√3; sin60=√3/2, then

2) 0.5+0.5=1.

4 0

2 years ago

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If you borrow $1,200 for 3 years at an annual interest rate of 4% how much will u pay?

Anastaziya [24]

I=Prt
I=$1,200(0.04)3
I=$144

7 0

3 years ago

Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4

steposvetlana [31]

$f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}$

$\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}$

6 0

3 years ago

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