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CaHeK987 [17]
3 years ago
15

Approximate √52 to the tenths place

Mathematics
2 answers:
Kitty [74]3 years ago
8 0
7.2
You take the square root in your calculator
Anestetic [448]3 years ago
5 0
7.2 is the answer i hope this helps!
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642 ÷ 5 standard algorithm
damaskus [11]

642/5= 128.4


i hope this helps

7 0
3 years ago
Read 2 more answers
1. Determine if each pair of rates are equivalent (Equal) Explain your reasoning: 12 posters for 36 students and 21 posters for
Sloan [31]

<em>Answer:264 students</em>

Step-by-step explanation:You have to add to get you answer.I'll show you how I got 264:

12+12=24

24+36=60

60+36=96

96+21=117

117+21=138

138+63=201

201+63=264

Your answer is: 264 students

5 0
3 years ago
!!20 points!!! Determine which postulate or theorem can be used to prove that ABC = <br> DCB
maria [59]
I think the answer is A, SAS
5 0
3 years ago
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A recipe says that 1 3/4 cups of baking soda are needed to make 1 batch of a homemade cleaning product, as represented below. Ho
RSB [31]

Answer:

4 3/8 cups of baking soda

Step-by-step explanation:

1 3/4 cups of baking soda are needed to make 1 batch of a homemade cleaning product,

Cups of baking soda : batches of homemade cleaning

1 3/4 cups : 1 batch

How many total cups of baking soda I needed to make 2 1/2 batches of the cleaning product?

Let x = total cups of baking soda needed

Cups of baking soda : batches of homemade cleaning

x cups : 2 1/2 batches

Equate the ratios

1 3/4 cups : 1 batch = x cups : 2 1/2 batches

7/4 ÷ 1 = x ÷ 5/2

7/4 × 1/1 = x * 2/5

7/4 = 2/5x

Divide both sides by 2/5

x = 7/4 ÷ 2/5

= 7/4 × 5/2

Cross product

x = 35/8

= 4 3/8 cups of baking soda

3 0
3 years ago
Can someone check my answer if I am incorrect please answer this question please answer this question correctly and please show
Elena-2011 [213]

Answer:

2 + (-7) = (-5)

Step-by-step explanation:

Correct problem and method of solving, just miscounted!

It should be + (-7) instead of + (-6).

This also changes the answer to (-5) instead of (-4).

4 0
3 years ago
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