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lesya692 [45]
3 years ago
10

Crane, Inc. manufactures two products: missile range instruments and space pressure gauges. During April, 50 range instruments a

nd 200 pressure gauges were produced, and overhead costs of $72,750 were estimated. An analysis of estimated overhead costs reveals the following activities. Activities Cost Drivers Total Cost 1. Materials handling Number of requisitions $30,000 2. Machine setups Number of setups 23,750 3. Quality inspections Number of inspections 19,000 $72,750 The cost driver volume for each product was as follows. Cost Drivers Instruments Gauges Total Number of requisitions 375 625 1,000 Number of setups 175 300 475 Number of inspections 225 250 475
Business
1 answer:
grigory [225]3 years ago
4 0

Answer:

Requirement: <em>Determine the overhead rate for each activity "Materials handling, Machine setups, Quality inspections"</em>

<em />

Materials handling overhead rate = Total cost / Cost driver volume

Materials handling overhead rate = $30,000 / 1,000

Materials handling overhead rate = $30

Machine setups overhead rate = Total cost / Cost driver volume

Machine setups overhead rate = $23,750 / 475

Machine setups overhead rate = $50

Quality inspections overhead rate = Total cost / Cost driver volume

Quality inspections overhead rate = $19,000 / 475

Quality inspections overhead rate = $40

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a) 0.0260

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Explanation:

a)

The bag contains:

r = 9 (number of red marbles)

w = 5 (number of white marbles)

b = 6 (number of blue marbles)

So, the total number of marbles in the bag at the beginning is:

n=9+5+6=20

At the 1st attempt, the probability of choosing a red marble is:

p(r)=\frac{r}{n}=\frac{9}{20} (1)

At the 2nd attempt, the 1st red marble is not placed back, so now the number of marbles is (n-1), while the number of red marbles left is (r-1). So the probability of choosing another red marble at the 2nd attempt is

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With a similar argument, the probabilities of selecting a red marble in the 3rd and 4th attempt are

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Therefore, the probability of drawing 4 red marbles in the first 4 attempts without replacing is:

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b)

At the 1st draw, the probability that the marble is not red is:

p(r^c)=1-p(r)=1-\frac{9}{20}=\frac{11}{20}

At the 2nd draw, there are 9 red marbles left and 19 total marble left. So, the probability of NOT drawing a red marble is:

p(r^c)=1-\frac{9}{19}=\frac{10}{19}

At the 3rd draw, there are 9 red marbles left and 18 total marbles left. So, the probability of NOT drawing a red marble is:

p(r^c)=1-\frac{9}{18}=\frac{9}{18}

Finally, with a similar argument the probability of NOT drawing a red marble at the 4th and last attempt is:

p(r^c)=\frac{8}{17}

So, the total probability of drawing 4 non-red marbles in the first 4 attempts is:

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