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enot [183]
3 years ago
14

Pls help asap no files though

Mathematics
1 answer:
xeze [42]3 years ago
5 0

Answer:

About 10 for A and B

Step-by-step explanation:

Just count the little boxes :)

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True or false. the function is the product of 400 and a factor that does not depend on the initial number of visitors
Aleks [24]

Answer:

true

Step-by-step explanation:

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3 years ago
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The number 3 was typed into cell A1 of a spreadsheet, while in cells A2-A7, formulas themselves, what would be the value display
beks73 [17]

Answer:

It's C... I just got that............................

Step-by-step explanation:

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3 years ago
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At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper
Korvikt [17]

Answer:

90.67% probability that John finds less than 7 golden sheets of paper

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it contains a golden sheet of paper, or it does not. The probability of a container containing a golden sheet of paper is independent of other containers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper containers.

This means that p = 0.3

14 of these containers of paper.

This means that n = 14

What is the probability that John finds less than 7 golden sheets of paper?

P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{14,0}.(0.3)^{0}.(0.7)^{14} = 0.0068

P(X = 1) = C_{14,1}.(0.3)^{1}.(0.7)^{13} = 0.0407

P(X = 2) = C_{14,2}.(0.3)^{2}.(0.7)^{12} = 0.1134

P(X = 3) = C_{14,3}.(0.3)^{3}.(0.7)^{11} = 0.1943

P(X = 4) = C_{14,4}.(0.3)^{4}.(0.7)^{10} = 0.2290

P(X = 5) = C_{14,5}.(0.3)^{5}.(0.7)^{9} = 0.1963

P(X = 6) = C_{14,6}.(0.3)^{6}.(0.7)^{8} = 0.1262

P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0068 + 0.0407 + 0.1134 + 0.1943 + 0.2290 + 0.1963 + 0.1262 = 0.9067

90.67% probability that John finds less than 7 golden sheets of paper

7 0
3 years ago
How to solve the inequality
beks73 [17]

Answer:

x\geq 19/6

Step-by-step explanation:

1. Multiply both sides by 6 (the LCM of 6,3)

5/2 + 3-x <= 2(x-2)

2. Simplify 5/2+3-x to 11/2-x

11/2 - x<=2 (x-2)

3. Expand.

11/2-x<= 2x-4

4. Add x to both sides.

11/2<= 2x-4+x

5. Simplify 2x-4+x to 3x-4.

11/2<=3x-4

6. Add 4 to both sides.

11/2+4<=3x

7. Simplify 11/2+4 to 19/2

19/2<=3x

8. Divide both sides by 3

19/2 /3 <=x

9. Simplify 19/2 /3 to 19/2*3

19/2*3<=x

10. Simplify 2*3 to 6

19/6<=x

11. Switch sides.

x>= 19/6

Hope this helps!

4 0
3 years ago
Simplify the following expression.
tankabanditka [31]
The answer is 2/3

or in decimal form: 0.6 repeated
7 0
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