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liubo4ka [24]
3 years ago
10

Y=3*? What is the inverse

Mathematics
1 answer:
jeka943 years ago
4 0

Answer:

the inverse is none hope this helps :)

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Given that 2^x = 7, find the value of 4^x-1.
Helga [31]

4=2^2\\\\4^x=(2^2)^x=(2^x)^2=7^2=49\\\\4^x-1=49-1=48


If\ is\ 4^{x-1},\ then\\\\4^{x-1}=\dfrac{4^x}{4}=\dfrac{49}{4}=12\frac{1}{4}

Used:\\\dfrac{a^n}{a^m}=a^{n-m}

4 0
3 years ago
Binomial factor of 25x2 + 40xy + 16y2 ?
Reika [66]

Answer:

  (5x +4y)^2

Step-by-step explanation:

The first and last terms are both perfect squares, and the middle term is twice the product of their roots. That means the trinomial is the perfect square trinomial ...

  25x^2 +40xy +16y^2 = (5x +4y)^2

_____

It matches the pattern ...

  a^2 +2ab +b^2 = (a +b)^2

8 0
3 years ago
In y=3x+1, where does the line cross the y axis?
dimaraw [331]

Answer: when x =0

Step-by-step explanation:

Y=3(0)+1

0+1

1

4 0
3 years ago
The region in the first quadrant bounded by the x-axis, the line x = ln(π), and the curve y = sin(e^x) is rotated about the x-ax
charle [14.2K]
First, it would be good to know that the area bounded by the curve and the x-axis is convergent to begin with.

\displaystyle\int_{-\infty}^{\ln\pi}\sin(e^x)\,\mathrm dx

Let u=e^x, so that \mathrm dx=\dfrac{\mathrm du}u, and the integral is equivalent to

\displaystyle\int_{u=0}^{u=\pi}\frac{\sin u}u\,\mathrm du

The integrand is continuous everywhere except u=0, but that's okay because we have \lim\limits_{u\to0^+}\frac{\sin u}u=1. This means the integral is convergent - great! (Moreover, there's a special function designed to handle this sort of integral, aptly named the "sine integral function".)

Now, to compute the volume. Via the disk method, we have a volume given by the integral

\displaystyle\pi\int_{-\infty}^{\ln\pi}\sin^2(e^x)\,\mathrm dx

By the same substitution as before, we can write this as

\displaystyle\pi\int_0^\pi\frac{\sin^2u}u\,\mathrm du

The half-angle identity for sine allows us to rewrite as

\displaystyle\pi\int_0^\pi\frac{1-\cos2u}{2u}\,\mathrm du

and replacing v=2u, \dfrac{\mathrm dv}2=\mathrm du, we have

\displaystyle\frac\pi2\int_0^{2\pi}\frac{1-\cos v}v\,\mathrm dv

Like the previous, this require a special function in order to express it in a closed form. You would find that its value is

\dfrac\pi2(\gamma-\mbox{Ci}(2\pi)+\ln(2\pi))

where \gamma is the Euler-Mascheroni constant and \mbox{Ci} denotes the cosine integral function.
5 0
4 years ago
The frequency of the musical note G4 is about 392.00 Hz.
rewona [7]

Answer:

196.00 Hz

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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