Work out the difference between 5/9and4/9

Mathematics

1 answer:

tatiyna3 years ago

7 0

Answer:

1/9

Step-by-step explanation:

Subtract them

5/9-4/9=1/9 Answer

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5 diferrent representations of the value 3

Minchanka [31]

Does this mean:
1x3=3
4-1=3
2+1=3
5-2=3
6/2=3
?

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3 years ago

Read 2 more answers

What are the period and phase shift for f(x) = 3 tan(4x + π)?

Y_Kistochka [10]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\

\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ horizontal or "phase" shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now.. with that template above in mind, let's see yours

$\bf \begin{array}{lllllll}
f(x)=&3tan(&4x+&\pi )\\
f(x)=&3tan(&4x+&1\pi )&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

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3 years ago

Find the area of the trapezoid.

Aliun [14]

The area equation is $A=\frac{a+b}{2} *h$

the trapezoid is actually on its side
so a=10.2
b=12.2
h=12.6

$A=\frac{10.2+12.2}{2} *12.6\\
=\frac{22.4}{2} *12.6\\
=11.2*12.6\\
=141.12\\$