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oee [108]
3 years ago
6

Please help I just need #5-8

Mathematics
2 answers:
olga_2 [115]3 years ago
7 0
13 and i cant see number 8
lora16 [44]3 years ago
3 0
I don't want to do this for you, I do, but I want you to learn, so, use PEMDAS(Parenthesis, Exponents,MUltiply,Divide,Add,Subtract.) Fine. problem 6=d  8=a Well 7 is  little tricky. The answer is 10, but there is no a,b,c,or d that says it's the value. Example (F=10) there is nothing like that. Did you cut it off?
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The square pyramid shown below has a base with sides of 10 units. The slant height of the pyramid is 8 units. What is the vertic
yawa3891 [41]

Answer:

h = 6.2 units

Step-by-step explanation:

Given triangle ABC is a right triangle with the measures of the two sides,

BC = \frac{10}{2} = 5 units

AC = 8 units

By applying Pythagoras theorem in the given triangle,

AC² = AB² + BC²

8² = AB² + 5²

AB² = 64 - 25

AB = √39

AB = 6.24 units

AB ≈ 6.2 units

7 0
3 years ago
Question: F=d+e+t, solve for t.
Komok [63]
           F = d + e + t   Flip the sides to put t on the left
d + e + t = F              Subtract d from both sides
      e + t = F - d        Subtract e from both sides
            t = F - d - e
7 0
3 years ago
Read 2 more answers
The area of the rhombus is 540 cm2; the length of one of its diagonals is 4.5 dm. What is the distance between the point of inte
malfutka [58]

1. The area of the rhombus can be found by the formula

A=\dfrac{d_1\cdot d_2}{2}, where d_1,\ d_2 are rhombus's diagonals.

Note that d_1=4.5\ dm=45\ cm, then

540=\dfrac{45\cdot d_2}{2},\\ \\540\cdot 2=45d_2,\\ \\d_2=24\ cm.

2. The diagonals of rhombus are perpendicular and are bisectors of each other. Then the triangle formed with halfs of diagonals is right triangles with legs

\dfrac{d_1}{2}=22.5\ cm,\ \dfrac{d_2}{2}=12\ cm.

The hypotenuse of this triangle is the rhombus's side. By the Pythagorean theorem

\text{rhombus's side}^2=(22.5)^2+12^2=506.25+144=650.25,\\ \\\text{rhombus's side}=25.5\ cm.

3. The distance between the point of intersection of the diagonals and the side of the rhombus is the height of right triangle considered above.

Use twice the Pythagorean theorem to find this height:

\left\{\begin{array}{l}x^2+h^2=12^2\\(25.5-x)^2+h^2=22.5^2,\end{array}\right.

where x is projection of leg 12 cm and h is height.

Subtract the first equation from the second:

(25.5-x)^2+h^2-x^2-h^2=22.5^2-12^2,\\ \\650.25-51x=506.25-144,\\ \\51x=650.25-362.25=288,\\ \\x=\dfrac{96}{17}\ cm.

Then

h^2=144-\left(\dfrac{96}{17}\right)^2=144-\dfrac{9216}{289}=\dfrac{32400}{289},\\ \\h=\dfrac{180}{17}\ cm.

Answer: h=\dfrac{180}{17}\ cm.

7 0
3 years ago
Read 2 more answers
Can some one help me please
GREYUIT [131]

Answer:

Acc to the exponential rule

{[A^m]} ^2

A ^m*n

Hence A raise to 3 whole raise to 2 is equal to

A raise to 3*2=6

That is A raise to 6

4 0
3 years ago
Evaluate if c = 2 and d = –3.
klio [65]

Answer:

B : -2

Step-by-step explanation:

3(2) \div ( - 3) \\ 6 \div ( - 3) \\  - 2

3 0
4 years ago
Read 2 more answers
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