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sergeinik [125]
4 years ago
15

A random variable x is uniformly distributed over the interval (-4, 6). Find the standard deviation of x. (Note: Uniform distrib

ution is a distribution where the PDF value is the same across all x values)
Mathematics
1 answer:
Pachacha [2.7K]4 years ago
3 0

Answer:

The standard deviation of x is 2.8867

Step-by-step explanation:

The standard deviation of variable x that follows a uniform distribution is calculated as:

s = \sqrt{\frac{(b-a)^{2} }{12} }

Where (a,b) is the interval where x is defined.

So, replacing a by -4 and b by 6, the standard deviation is:

s = \sqrt{\frac{(6-(-4))^{2} }{12} }

s = \sqrt{\frac{(10)^{2} }{12} }

s=\sqrt{\frac{100}{12} }

s=\sqrt{8.3333}

s=2.8867

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Chen writes down a two digit number. He finds out that if he swapped the numbers, it would be three more than the 1/3 of the ori
inna [77]

Answer:

Step-by-step explanation:

From the information given,

Let the two digits that Chen writes down to be p and q

where,

q will be in the unit place and p will be in the tens place.

So, the value of the digit = 10p + q

So, if he swapped the number, he will have 10q + p

However,

the new number determined is thrice more than the 1/3 pf the original number.

i.e

the 1/3rd of the original number = \dfrac{1}{3}(10p+q)

=\dfrac{10p+q}{3}

thrice more than that will be = \dfrac{10p+q}{3} + 3

∴

\dfrac{10p+q}{3} + 3 = 10q+p

multiply through by 3, we have :

10p+q + 9 = 30q + 3p

collecting the like terms, we have:

10p - 3p +q -30q +9 = 0

7p - 29q +9 = 0

7p - 29q = -9

Therefore, p,q lie between 0 and 9

Therefore, the possibility of the original number is p = 7 and q = 2

8 0
4 years ago
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g100num [7]

Answer:

a>6

Step-by-step explanation:

1) Subtract 1 from both sides.

a>7-1

2) Simplify 7 - 1 to 6.

a>6

<u>Therefor, the answer is </u><u>a > 6</u>.

8 0
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maxonik [38]

ok so we see that TR is 17 units, so RV is the same amount

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now we know x=5 4x+1=21 and 9x-4=41

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Answer:

I wanna say its D. $259.67

Step-by-step explanation:

Some one should back my answer but I hope this helps you

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3 years ago
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Answer:

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3 years ago
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