What is the simplified expression for the expression below?
2 answers:
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Hi there!
<u>What we need to know:</u>
The three main trigonometric ratios are sine, cosine and tangent:
"Opposite" refers to the side opposite the angle that is not the hypotenuse.
"Hypotenuse" refers to the side opposite the right angle of a right triangle.
"Adjacent" refers to the side next to the angle that is not the hypotenuse.
"θ" is read as "theta". It just represents the angle.
Keep in mind that these three ratios only apply to right triangles.
You can use the mnemonic "soh-cah-toa" to help you remember these ratios.
<u>First question</u>
For the first question, we're given the angle with a measure of 56 degrees and the length of the <em>hypotenuse</em>. We must calculate <em>a</em>, which represents the side <em>adjacent </em>to the given angle.
Given the hypotenuse and the adjacent side, we know that we must use the cosine ratio:
Plug in the given information:
Isolate <em>a</em> by multiplying both sides by 13:
Solve using a calculator:
Therefore, <em>a</em> is equal to 7.3 when rounded to 1 decimal place.
<u>Other information you will need to know:</u>
In the above question, we needed to solve for a side. But what if we were given two sides and we needed to solve for an angle? For example:
In this case, we will use the inverse sine ratio:
Solve using a calculator:
Therefore, the angle would equal approximately 39 degrees.
I hope this helps!
Answer:
a) P(X∩Y) = 0.2
b) = 0.16
c) P = 0.47
Step-by-step explanation:
Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.
So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67
Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:
P(X∩Y) = P(X) + P(Y) - P(X∪Y)
P(X∩Y) = 0.36 + 0.51 - 0.67
P(X∩Y) = 0.2
On the other hand, the probability that he must stop at the first signal but not at the second one can be calculated as:
= P(X) - P(X∩Y)
= 0.36 - 0.2 = 0.16
At the same way, the probability that he must stop at the second signal but not at the first one can be calculated as:
= P(Y) - P(X∩Y)
= 0.51 - 0.2 = 0.31
So, the probability that he must stop at exactly one signal is: