Answer:
d. pxp +2pq
Explanation:
The formula for genotype frequency for a population in Hardy-Weinburg equilibrium is as under:
p² + 2pq + q² = 1
where, p = dominant allele
q = recessive allele
Here,
p² represents frequency of homozygous dominant genotype
2pq represents frequency of heterozygous genotype
q² represents frequency of homozygous recessive genotype
Also, although the genotypes p² & 2pq are different from each other yet phenotypically they both will collectively produce dominant trait i.e. free ear lobes not attached earlobes. So the term "p² + 2pq or pxp + 2pq" represents the frequency of the individuals who show the dominant phenotype in this particular population. Dominant phenotype will comprise 75% of the population.
<span>The two identical daughter cells resulting from
mitosis and cytokinesis are identical in the following ways:1. Mitosis
occurs when the nucleus of the cell divides into two identical nuclei,
each with the same type and number of chromosomes. The cell's DNA is
duplicated during this phase. Sometimes the cell's DNA isn't copied
properly resulting in cancer-type cells. 2. Cytokinesis is when the
cytoplasm divides into two identical daughter cells. Each cell is
genetically identical and both are a similar size.
</span>
Answer:
3:1
Explanation:
To find out the phenotypic ratio, we need to do a Punnet Square.
We know that R and I are the dominant alleles that produce red flowers, and r and i are the recessive traits.
<u> ║R ║ r</u>
<u>I ║RI║Ir</u>
<u>i ║Ri║ir</u>
The genotype ratio would be 3 because the dominant traits are present three times (RI, Ir, and Ri) and 1 for the recessive trait since it only appears once in the Punnet Square (ir). In conclusion, the phenotypic ratio form the roses are 3:1
Answer:
Heat from the air will move to the book
Explanation:
B