NOT is the boolean operator which omits information from the search parameters.
Answer:
Five variations od BLAST are as following:-
- BLASTP
- BLASTX
- TBLASTX
- BLASTN
- TBLASTN
Explanation:
BLASTP - Searches a protein database with a protein sequence.
BLASTX - This program searches protein database using a translated nucleotide sequence.
TBLASTX - Searches DNA databases using a protein query.
BLASTN -Searches a nucleotide sequence against DNA database.
TBLASTN - Searches nucleotide sequence to a DNA database.
ANSWER:
1)i. The relationship is a degree of 2 ( i.e Binary). The cardinality of the relationship is One-to-Many.
ii. The model is from piano description to piano manufacturer.
PIANO:
Model name
Model number
Serial number
Manufacturing completion date
MANUFACTURER:
Ebony and Ivory
2)i. The relationship is a degree of 2 ( i.e Binary). The cardinality of the relationship is Many-to-Many.
ii. The model is from piano description to Technician.
PIANO:
Model name
Model number
Serial number
Manufacturing completion date
TECHNICIAN
Employee number
Specialty
3)i. The relationship is a degree of 2 (i.e Binary). The cardinality of the relationship is Many-to-One.
ii. The model is from Technician to Technician
TECHNICIAN:
Lower rank
TECHNICIAN:
Higher rank
Answer:
The probability that you have the disease, given that your test is positive is ≈ 0.0098
Explanation:
This is a conditional probability problem.
Let P(A|B) denote the conditional probability of A given B and it satisfies the equation
- (1) P(A|B) = P(A) × P(B|A) / P(B)
We have the the probabilities:
- P(Testing Positive | Having Disease) =0.99
- P(Testing Negative | Not Having Disease) =0.99
- P(Testing Positive | Not Having Disease) = 1-0.99=0.01
- P(Having Disease) = 0.0001 (striking only one in 10,000 people)
- P(Not Having Disease)= 1 - 0.0001 = 0.9999
<u>We can calculate</u>:
P(Testing Positive) =
P(Having Disease) × P(Testing Positive | Having Disease) + P(Not Having Disease) × P(Testing positive | Not Having Disease ) = 0.0001×0.99 + 0.9999×0.01 =0.010098
<u>from </u><u>(1) </u><u>we have the equation</u>:
P(Having Disease|Testing Positive)=P(Having Disease) × P(Testing Positive | Having Disease)/ P(Testing Positive) = 0.0001×0.99/0.010098≈0.0098
Thus, the probability that you have the disease, given that your test is positive is ≈ 0.0098
