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Marina CMI [18]
3 years ago
5

Why do you feel an organization has multiple layers of security in place to protect its operation?

Computers and Technology
1 answer:
aalyn [17]3 years ago
4 0

The purpose of including multiple layers in your network security<span> is to make sure that </span>each single defense component has a backup<span> in the case of a flaw or missing coverage. The individual strengths of each layer also cover any gaps that other defenses may lack.</span>

With this assumption in mind, each individual layer in a multi-layered security approach focuses on a specific area where the malware could attack. By working in concert, these layers of security offer a better chance of stopping intruders from breaching company networks than using a single solution.

The types of security layers you can use in your network defense include:

<span>Web protectionPatch managementEmail security and archivingVulnerability assessment and analyticsAntivirus softwareData encryptionFirewallsDigital certificatesAnti-spam and spam filtersPrivacy controls</span>

<span>Having multiple layers of security in place is crucial for MSPs who protect data at all levels and across numerous applications and devices. Not only should data stay safe, but so should the methods of communication and the network where information is transferred.</span>

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C++ Code

#include
using namespace std;

bool match(const char exp[],const int s)
{
// declare a character array to perform stack operations
char stack[s];

// declare top and initialize to -1 and flag to 0
int top=-1,i,flag=0;

// visit all characters in the expression string
for(i=0;i {
// if the character is [ or ( or { then push it into stack
if(exp[i]=='[' || exp[i]=='(' || exp[i]=='{')
{
top++;
stack[top]=exp[i];
}
// if the character is ] or ) or } then check conditions
else if(exp[i]==']' || exp[i]==')' || exp[i]=='}')
{
// check stack is empty or not
if(top!=-1)
{
// check all possible failure conditions
if(exp[i]==')' && (stack[top] == '{' || stack[top]=='['))
{
flag = 1;
break;
}
else if(exp[i]==']' && (stack[top] == '{' || stack[top]=='('))
{
flag = 1;
break;
}
else if(exp[i]=='}' && (stack[top] == '(' || stack[top]=='['))
{
flag = 1;
break;
}
top--;
}
else
{
flag=1;
break;
}
}
}
// after visiting all characters of expression string check if stack is not empty and flag is 1. if any one of the condition is true return false. otherwise return true

if(top>=0 || flag==1)
return false;
else
return true;
}

int main()
{

// declare character array to store expression
char exp[10000];
cout<<"Enter an Expression"<
// read expression from user
cin.getline(exp, 10000);
int s=0;

// find the length of the expression string
for(int i=0;exp[i]!='\0';i++)
{
s++;
}

// call the match function
bool status = match(exp,s);

// print the result based on value returned by match() function
if(status == 1)
cout<<"true"< else
cout<<"false"<
}


Sample Input/Output is attached

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