Answer:
0
Step-by-step explanation:
2/3*2/2=4/6. 4/6-4/6=0
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Answer:
<h3>Hence required integers are 11 and 13</h3>
Let x an odd positive integer
Then, according to question
x^2 +(x+2)^2=290
2x^2 +4x−286=0
x^2 +2x−143=0
x ^2+13x−11x−143=0
(x+13)(x−11)=0
x=11 as x is positive
Hence required integers are 11 and 13
Step-by-step explanation:
Hope it is helpful....
Answer:
<h2><u>b = 2 or b = -2</u></h2>
Explanation:
|4b + 4| = |2b + 8|
<em>Solve absolute value</em>
|4b + 4| = |2b + 8|
Either 4b + 4 = 2b + 8 or 4b + 4 = −(2b + 8)
4b + 4 = 2b + 8 <em>(Possibility 1)</em>
4b + 4 − 2b = 2b + 8 − 2b <em>(Subtract 2b from both sides)</em>
2b + 4 = 8
2b + 4 − 4 = 8 − 4 <em>(Subtract 4 from both sides)</em>
2b = 4
2b / 2 = 4 / 2 <em>(Divide both sides by 2)</em>
b = 2
4b + 4 = −(2b + 8) <em>(Possibility 2)</em>
4b + 4 = −2b − 8 <em>(Simplify both sides of the equation)</em>
4b + 4 + 2b = −2b − 8 + 2b <em>(Add 2b to both sides)</em>
6b + 4 = −8
6b + 4 − 4 = −8 − 4 <em>(Subtract 4 from both sides)</em>
6b = −12
6b / 6 = -12 / 6 <em>(Divide both sides by 6)</em>
b = -2
<h2><u>b = 2 or b = -2</u></h2>