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3 years ago

Someone please help with number 13

Mathematics

2 answers:

Zielflug [23.3K]3 years ago

5 0

if i'm not mistaking, the answer is 1/4, hope this helped.

natali 33 [55]3 years ago

3 0

23/30 is the answer. That is because it is asking what the fraction of april is taken up by non- holiday weekends and when you ad both of the fractions you get the answer.

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What is 6 to the fourth power times 6 to the fourth power

wel

Answer:

6^8

Step-by-step explanation:

6^4 * 6^4

We know that a^b * a^c = a^(b+c)

6^4 * 6^4 = 6^(4+4) = 6^8

7 0

3 years ago

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denis-greek [22]

-14/5 , -2.8 and yeah

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3 years ago

Which function has the same domain as y = 2 StartRoot x EndRoot

snow_lady [41]

The answer is A. Y=square root of 2x

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3 years ago

Which expression is equivalent to the expression below? StartFraction 6 c squared 3 c Over negative 4 c 2 EndFraction divided by

Fudgin [204]

The given equation $(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)$ is equivalent to the expression -3c.

Given that, the expression can be written as.

$(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)$

By simplifying the above equation,

$\dfrac{6c^2+3c}{-4c+2}\div \dfrac{2c+1}{4c-2}$

By taking out the common terms from the equation,

$\dfrac{3c(2c+1)}{2(-2c+1)}\div\dfrac{2c+1}{2(2c-1)}$

By simplifying the above equation by cancel out the common factors.

$\dfrac{3c}{-2c+1} \div \dfrac{1}{2c-1}$

Now, by taking (-1) common from (-2c+1) we get,

$\dfrac{3c}{-1(2c-1)} \div \dfrac{1}{2c-1}$

By simplifying the above equation, we get the expression,

$-3c$

So the given equation $(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)$ is equivalent to the expression -3c.

For more details, follow the link given below.

brainly.com/question/1301963.

7 0

3 years ago

Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest

kicyunya [14]

P= 1/2
Both 3 and 1 are factors of 21

7 0

3 years ago

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