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9966 [12]
3 years ago
15

Someone please help with number 13

Mathematics
2 answers:
Zielflug [23.3K]3 years ago
5 0

if i'm not mistaking, the answer is 1/4, hope this helped.

natali 33 [55]3 years ago
3 0

23/30 is the answer. That is because it is asking what the fraction of april is taken up by non- holiday weekends and when you ad both of the fractions you get the answer.

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Given the vectors, a=3i+4j, b=-2i+5j, c=10i-j, d=-1/3i+5/2j, find -0.4a-0.3b+0.2d=?
sveta [45]

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-\frac{2}{3}i - \frac{13}{5}j

Step-by-step explanation:

-0.4(3i + 4i) - 0.3(-2i + 5j) + 0.2(-\frac{1}{3}i + \frac{5}{2}j)

-1.2i - 1.6j + 0.6i - 1.5j - \frac{0.2}{3}i + 0.5j

Converting to fraction form;

-\frac{6}{5}i + \frac{3}{5}i - \frac{1}{15}i - \frac{8}{5}j - \frac{3}{2}j + \frac{1}{2} j

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<u>Solving the j part;</u>

\frac{-16j-15j+5j}{10} = -\frac{13}{5}j

So -0.4a - o.3b + 0.2d =  -\frac{2}{3}i - \frac{13}{5}j

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