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3 years ago

If you have a rectangular bathtub, what would represent the volume?

Mathematics

2 answers:

zlopas [31]3 years ago

7 0

The amount of water that fills up the tub !

astraxan [27]3 years ago

7 0

B)the amount of water that fills the tub

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X= 2,3,4 y= 11, 16.5, 22

marshall27 [118]

X = is How many ex’s and O’s do you have?
2 is,I see
3 is,how you do
4 is, LOVE
Y= ask first
11, is make a wish
16.5, divide by 4. Then you define what remains 5
2+2=4 Love again

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3 years ago

How would the graph of y = x change if the y-intercept is changed to -2?

Vladimir [108]

Answer:

Step-by-step explanation:

y= x - 2

the graph would be parallel to y=x and every point would be shifted down 2 units

If you took any point on y = x and represented it as (x,y) then the new point would be (x,y - 2)

5 0

3 years ago

An equation of a hyperbola is given.

siniylev [52]

Answer:

The vertices are $\left(3,\:0\right),\:\left(-3,\:0\right)$ .

The foci are $\left(3\sqrt{5},\:0\right),\:\left(-3\sqrt{5},\:0\right)$ .

The asymptotes are $y=2x,\:y=-2x$ .

b) The length of the transverse axis is 6.

c) See below.

Step-by-step explanation:

$\frac{\left(x-h\right)^2}{a^2}-\frac{\left(y-k\right)^2}{b^2}=1$ is the standard equation for a right-left facing hyperbola with center $\left(h,\:k\right)$ .

The vertices $\:\left(h+a,\:k\right),\:\left(h-a,\:k\right)$ are the two bending points of the hyperbola with center $\:\left(h,\:k\right)$ and semi-axis a, b.

Therefore,

$\frac{x^2}{9}-\frac{y^2}{36}=1$ , is a right-left Hyperbola with $\:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6$ and vertices $\left(3,\:0\right),\:\left(-3,\:0\right)$ .

For a right-left facing hyperbola, the Foci (focus points) are defined as $\left(h+c,\:k\right),\:\left(h-c,\:k\right)$ where $c=\sqrt{a^2+b^2}$ is the distance from the center $\left(h,\:k\right)$ to a focus.

Therefore,

$\frac{x^2}{9}-\frac{y^2}{36}=1$ , is a right-left Hyperbola with $\:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6$ $c=\sqrt{3^2+6^2}= 3\sqrt{5}$ and foci $\left(3\sqrt{5},\:0\right),\:\left(-3\sqrt{5},\:0\right)$

The asymptotes are the lines the hyperbola tends to at $\pm \infty$ . For right-left hyperbola the asymptotes are: $y=\pm \frac{b}{a}\left(x-h\right)+k$

Therefore,

$\frac{x^2}{9}-\frac{y^2}{36}=1$ , is a right-left Hyperbola with $\:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6$ and asymptotes

$y=\frac{6}{3}\left(x-0\right)+0,\:\quad \:y=-\frac{6}{3}\left(x-0\right)+0\\y=2x,\:\quad \:y=-2x$

b) The length of the transverse axis is given by $2a$ . Therefore, the lenght is 6.

c) See below.

4 0

4 years ago

Help ME PLSSS HURRY!!!!!!

Scilla [17]

Answer:

None of them are proportiionsal

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Can some one help me plz I really need help

Sonbull [250]

1. 2x + 50 = 100
subtract 50 on both sides and then divide by 2.

x = 25

180 - 100 = 80

m
2. 7x - 4 = 87
add 4 on both sides and divide by 7.

x = 13

180 - 87 = 93

m
3. 5x - 2 = 38
add both sides by 2 and divide by 5.

x = 8

180 - 38 = 142

m
4. 14 + 6x = 134
subtract both sides by 14 and divide by 6.

x = 20

180 - 134 = 46

m
5. x = 53

m
6. x = 14

m

6 0

3 years ago