Answer:
Step-by-step explanation:
50.
line AB that has the points (2,5) and (9,2) hhas the slope
m= (y2-y1) / (x2-x1)= 5-2 / 2-9 = 3/-7 = -3/7
Parallel line have the same slope so m= -3/7 for the line that has the point (-3,4).
Point-slope equation is y-y1 = m (x-x1), y -4 = -3/4 (x+3) or
you can writte it as y= (-3/4)x - 9/4 +16/4 so y = (-3/4)x + 7/4
51.
line PQ has slope m= -6+1 / 4-6 = -5/-2 = 5/2
Perpendicular lines have their slope negative reciprocal of eachother so the line that goes trough the point (1,3) has the slope m= -2/5
y-3 = -2/5 (x-1)
Answer:
Step-by-step explanation:
<u>Exponential function:</u>
<u>Ordered pairs given:</u>
<u>Substitute x and y values to get below system:</u>
<u>Divide the second equation by the first one and solve for b:</u>
- 80/10 = b³
- b³ = 8
- b = ∛8
- b = 2
<u>Use the first equation and find the value of a:</u>
<u>The function is:</u>
Answer:
12 45 67 88 90
Step-by-step explanation:
For this you need to solve by elmination
