All categories

3 years ago

HELP I NEED HELP I WILL GIVE YOU THE CROWN pls help

Mathematics

1 answer:

Dovator [93]3 years ago

7 0

Answer:

Step-by-step explanation:

15<r thats how it would look like

You might be interested in

Find the missing coefficients <br><br><br>y=ax^2-10x+c <br>vertex :(-5,20)

Citrus2011 [14]

Remember, for $y=ax^2+bx+c$ the x value of the vertex is $\frac{-b}{2a}$

so
given
x value of vertex is -5
and
$y=ax^2-10x+c$
$\frac{-b}{2a}=\frac{-(-10)}{2a}=\frac{10}{2a}=$
$\frac{5}{a}=-5$
multiply both sides by a
5=-5a
divvide both sides by -5
-1=a
a=-1

$y=-1x^2-10x+c$
comlete the square
remember if we do
$y=a(x-h)^2+k$ (h,k) is the vertex
I know, we can subsitute the known values of te vertex
-5 for h and 20 for k then expand

$y=-1(x-(-5))^2+20$
$y=-1(x+5)^2+20$
$y=-1(x^2+10x+25)+20$
$y=-1x^2-10x-25+20$
$y=-1x^2-10x-5$

a=-1
c=-5

5 0

3 years ago

Find the volume and surface area

kompoz [17]

$\bf \begin{array}{llll} \stackrel{\textit{volume of a cylinder}}{V=\pi r^2 h}\\\\ V=\pi (8)^2(3)\\\\ V=192\pi \\\\ V\approx 603.19 \end{array}~\hfill \begin{array}{llll} \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=8\\ h=3 \end{cases} \end{array}~\hfill \begin{array}{llll} \stackrel{\textit{surface area of a cylinder}}{SA=2\pi r(h+r)}\\\\ SA=2\pi (8)(3+8)\\\\ SA=16\pi (11)\\\\ SA=176\pi \\\\ SA\approx 552.92 \end{array}$

7 0

3 years ago

Guysssss I'm struggling in mathh :( I need help

Sedaia [141]

Answer:

The first two is x=60

Step-by-step explanation:

1.5/90 = 1/x

1.5x = 90 x 1

1.5x/1.5 = 90/1.5

x = 60

5 0

4 years ago

Read 2 more answers

The two-way table shows the ages of the players on different sOCcer teams.

Tomtit [17]

**Answer**
The true statement is: The probability that a randomly selected player on Team C is 10 years old is 5/16

please mark me brainliest, happy holidays :)

6 0

3 years ago

STRUCTURE Write the ratio of the side lengths of the two cubes described in simplest form.

nordsb [41]

The answer is 24 because u have multiple it

6 0

3 years ago