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Delvig [45]
3 years ago
8

Which value of x would make NO || Kj?

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
6 0

Answer:

x = 8

Step-by-step explanation:

Given

The attached figure

Required

Find x

To find x, we make use of the following equivalent ratios:

LN : LO = NK:OJ

This gives:

(x-3) : (x - 4) = (x +2) : (x)

Convert to fractions

\frac{x-3}{x-4} = \frac{x+2}{x}

Cross Multiply

x(x-3) = (x-4)(x+2)

Open brackets

x^2-3x = x^2 -4x +2x - 8

Collect Like Terms

x^2 - x^2-3x +4x -2x =- 8

-3x +4x -2x =- 8

-1x =- 8

-x =- 8

Multiply through by -1

-1 * -x =- 8*-1

x = 8

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The triangles in the image are similar.<br> Solve for x.<br> A) 7 <br> B) 6 <br> C) 10 <br> D) 5
Natalka [10]

ANSWER

A) 7

EXPLANATION

The given triangles are similar

Hence the corresponding sides are in the same proportion.

\frac{3x + 4}{30}  =  \frac{30}{36}

Simplify the right hand side:

\frac{3x + 4}{30}  =  \frac{5}{6}

Cross multiply;

6(3x+4)=5×30

Expand

18x+24=180

18x=150-24

18x=126

x =  \frac{126}{18}  = 7

4 0
3 years ago
Which products result in a difference of squares? Select three options. (x minus y)(y minus x) (6 minus y)(6 minus y) (3 + x z)(
ValentinkaMS [17]

Answer:

Third option: (3 + xz)(-3 + xz)

Fourth option: (y^2 - xy)(y^2 + xy)

Sixth option: (64y^2 + x^2)(-x^2 + 64y^2)

Step-by-step explanation:

By definition, we can factor the Difference between two squares:

a^2 - b^2 = (a+b)(a-b)

In order to find which products results in a difference of squares, we need to check each option:

 1.\ (x - y)(y - x)=(x)(y)+(x)(-x)-(y)(y)+(-y)(-x)=xy-x^2-y^2+xy=-x^2-y^2+2xy

The product does not result in a difference of squares.

2.\ (6 - y)(6 - y)

Since the signs are equal (-), the product will not result in a difference of squares.

Using Distributive Property for the other options, we get:

3.\ (3 + xz)(-3 + xz)=(3)(-3)+(3)(xz)+(xz)(-3)+(xz)(xz)=\\\\=-9+3xz-3xz+x^2z^2=x^2z^2-9=(xz)^2-(3)^2

The product results in a difference of squares.

4.\ (y^2 - xy)(y^2 + xy)=(y^2)(y^2)+(y^2)(xy)-(xy)(y^2)-(xy)(xy)=\\\\=y^4+xy^3-xy^3-x^2y^2=y^4-x^2y^2=(y^2)^2-(xy)^2

The product results in a difference of squares.

5.\ (25x - 7y)(-7y + 25x)=(25x - 7y)(25x - 7y)

Since the signs are equal (-), the product will not result in a difference of squares.

6.\ (64y^2 + x^2)(-x^2 + 64y^2)=(64y^2 + x^2)(64y^2 - x^2)=\\\\=(64y^2)(-x^2)+(64y^2)(64y^2)+(x^2)(-x^2)+(x^2)(64y^2)=\\\\=-64y^2x^2+4096y^4-x^4+64y^2x^2=\\\\=4096y^4-x^4=(64y^2)^2-(x^2)^2

The product results in a difference of squares.

5 0
3 years ago
Read 2 more answers
Suppose that Y1, Y2,..., Yn denote a random sample of size n from a Poisson distribution with mean λ. Consider λˆ 1 = (Y1 + Y2)/
Burka [1]

Answer:

The answer is "\bold{\frac{2}{n}}".

Step-by-step explanation:

considering Y_1, Y_2,........, Y_n signify a random Poisson distribution of the sample size of n which means is λ.

E(Y_i)= \lambda \ \ \ \ \ and  \ \ \ \ \ Var(Y_i)= \lambda

Let assume that,  

\hat \lambda_i = \frac{Y_1+Y_2}{2}

multiply the above value by Var on both sides:

Var (\hat \lambda_1 )= Var(\frac{Y_1+Y_2}{2} )

            =\frac{1}{4}(Var (Y_1)+Var (Y_2))\\\\=\frac{1}{4}(\lambda+\lambda)\\\\=\frac{1}{4}( 2\lambda)\\\\=\frac{\lambda}{2}\\

now consider \hat \lambda_2 = \bar Y

Var (\hat \lambda_2 )= Var(\bar Y )

             =Var \{ \frac{\sum Y_i}{n}\}

             =\frac{1}{n^2}\{\sum_{i}^{}Var(Y_i)\}\\\\=\frac{1}{n^2}\{ n \lambda \}\\\\=\frac{\lambda }{n}\\

For calculating the efficiency divides the \hat \lambda_1 \ \ \ and \ \ \ \hat \lambda_2 value:

Formula:

\bold{Efficiency = \frac{Var(\lambda_2)}{Var(\lambda_1)}}

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8 0
3 years ago
[-3 1/4] greater or less than [-4]
Afina-wow [57]

Step-by-step explanation:

-3¼ is greater than -4

hope that helps you ;)

7 0
3 years ago
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The ratio 3:4:5:7 represents the ratio of apples to oranges to melons to grapefruit used to make a fruit salad. If you need 38 c
inessss [21]

Answer:

10

Step-by-step explanation:

3:4:<u>5</u>:7 added up is 19 so doubling it is-

6:8:<u>10</u>:14 =38

Hope this helps!

7 0
3 years ago
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