Please help

Mathematics

1 answer:

Lerok [7]2 years ago

8 0

Answer:

The sine function ranges between -1 and 1, so the minimum is -1 and the maximum is 1.

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What is the distance between the points (−4, 5) and (3, 5)?

puteri [66]

Answer:

idk but you should try getting photo math it's a

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2 years ago

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what is an equation of the line that passes through the point (5,1) and is parallel to the line x+y=9

Ede4ka [16]

Y=9-x is slope-intercept form of that line, which means it has a slope of -1. Parallel lines have the same slope, so the slope of this new line will also be -1.

To find the line that goes through (5,1), we can use a blank equation y=mx+b. We know that m=-1, so we can use the given point to find b:

y=mx+b
Y=-x+b
1=-5+b
6=b

So the line would be y=-x+6.

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2 years ago

Tom and Philip were given the graph of a linear function and asked to find the slope. Tom says that the slope is

Step2247 [10]

It’s no more to the problem?

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3 years ago

Can someone help me with (2/3 +1/4) • 5/6

strojnjashka [21]

Answer:

35/6

Step-by-step explanation:

add the fractions in parentheses by finding the common denominaters and adding. then multiply your answer by 5/6. :)

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3 years ago

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Need help with my homework

Volgvan

Answer:

$\displaystyle y=\frac{16-9x^3}{2x^3 - 3}$

$\displaystyle y=-\frac{56}{13}$

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

$\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}$

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

$\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3$