Answer:
The amount of oil was decreasing at 69300 barrels, yearly
Step-by-step explanation:
Given


Required
At what rate did oil decrease when 600000 barrels remain
To do this, we make use of the following notations
t = Time
A = Amount left in the well
So:

Where k represents the constant of proportionality

Multiply both sides by dt/A


Integrate both sides


Make A, the subject

i.e. At initial
So, we have:






Substitute
in 

To solve for k;

i.e.

So:

Divide both sides by 1000000

Take natural logarithm (ln) of both sides


Solve for k



Recall that:

Where
= Rate
So, when

The rate is:


<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>
7.6 grams of saturated fat times 4 Ounces
is 7.6x4, or 30.4
Answer:
Let A1 be original area
A2 dilated Area
A1=pi*d^2/4
=3.143*5^2/4
A1=19.63 unit square
A2= 3.143*15/4
A2=176.74 unit square
A2 is 9 times greater than A1
Hence the answer is B
Step-by-step explanation:
798054=700000+<u>90000</u>+<u>8000</u>+50+4
Hope it helps. Please do comment