Find the mode for the price of movie tickets at various theaters. $5, $4, $7, $9, $5, $8, $5, $3, $6, $5, $7, $4, $5, $4

Milo pays $3 per pound for dog food at Pat's Pet

Anna007 [38]

Answer:

Pat Pet's Palace

Step-by-step explanation:

Price of dog food at Pat Pet's Palace = $3 per pound

Price of dog food at Mark's Mutt Market can be estimated using the graph given.

The graph is a proportional graph, thus, the constant of proportionality between cost and pound = y/x

Using the coordinates of a point on the line, (2.5, 10), constant of proportionality or unit rate = y/x = 10/2.5 = 4.

This means the price of dog food at Mark's Mutt Market is $4 per pound.

Therefore, Milo would pay a lower price per pound for dog food at Pat Pet's Palace.

5 0

2 years ago

At noon, a hot-air balloon was at an elevation of 2,400 feet. One hour later it was at an elevation of 1,700 feet.

ASHA 777 [7]

Answer:

a.2,400-1700=

b. 700: the hot air balloon decreased height by 700 feet

4 0

2 years ago

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Assume z = x + iy, then find a complex number z satisfying the given equation. d. 2z8 – 2z4 + 1 = 0

kodGreya [7K]

Answer: complex equations has n number of solutions, been n the equation degree. In this case:

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i11,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i101,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i191,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i281,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i78,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i168,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i258,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i348,75°}$

Step-by-step explanation:

I start with a variable substitution:

$Z^{4} = X$

Then:

$2X^{2}-2X+1=0$

Solving the quadratic equation:

$X_{1} =\frac{2+\sqrt{4-4*2*1} }{2*2} \\X_{2} =\frac{2-\sqrt{4-4*2*1} }{2*2}$

$X=\left \{ {{0,5+0,5i} \atop {0,5-0,5i}} \right.$

Replacing for the original variable:

$Z=\sqrt[4]{0,5+0,5i}$

or $Z=\sqrt[4]{0,5-0,5i}$

Remembering that complex numbers can be written as:

$Z=a+ib=|Z|e^{ic}$

Using this:

$Z=\left \{ {{{\frac{\sqrt{2}}{2} e^{i45°} } \atop {{\frac{\sqrt{2}}{2} e^{i-45°} }} \right.$

Solving for the modulus and the angle:

$Z=\left \{ {{\sqrt[4]{\frac{\sqrt{2}}{2} e^{i45}} = \sqrt[4]{\frac{\sqrt{2}}{2} } \sqrt[4]{e^{i45}} } \atop {\sqrt[4]{\frac{\sqrt{2}}{2} e^{i-45}} = \sqrt[4]{\frac{\sqrt{2}}{2} } \sqrt[4]{e^{i-45}} }} \right.$

The possible angle respond to:

$RAng_{12...n} =\frac{Ang +360*(i-1)}{n}$

Been "RAng" the resultant angle, "Ang" the original angle, "n" the degree of the root and "i" a value between 1 and "n"

In this case n=4 with 2 different angles: Ang = 45º and Ang = 315º

Obtaining 8 different angles, therefore 8 different solutions.

3 0

2 years ago

Can SOMONE help ASAP I don’t understand the diameter of a circle plz show me how y’all got the awswer plz!!!! It’s the top one

babymother [125]

The area is 3.14 for number 6

6 0

2 years ago

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Solve for x<br> 2(x + 4) = -6<br> x=

polet [3.4K]

Answer:

Step-by-step explanation:

here you go mate :)

step 1

2(x + 4) = -6 solving for x

step 2

2(x + 4) = -6 simplify by distributing

2x+8=-6

step 3

2x+8=-6 subtract 8

2x=-14

step 4

2x=-14 look for the number that can divide them both like 2

2x/2=-14/2

answer

x=-7

4 0

2 years ago