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3 years ago

Plz help Fast!!!!! Which is faster 15 feet per second or 12 miles per hour

2 answers:

8 0

12 miles per hour is faster because 12 miles in one hour equals to 63,360 feet. If you multiply the amount of minutes in an hour to 15 you get to 54,000 feet so 15 feet per second in one hour would equal 54,000 feet making 12 miles per hour faster

Misha Larkins [42]3 years ago

3 0

I think 15 feet per second

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A line is perpendicular to y=2/3x +2/3 and intersects the point (-2,4). what is the equation of this perpendicular line?

TiliK225 [7]

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2 years ago

17 please help me......................

Vaselesa [24]

I think its (6.5+3.25)÷0.2=48.75

dont quote me on that, I tried and I'm not the best at math lol.
$(6.5 + 3.25) \div 0.2$

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3 years ago

Jamie rode her bike home for 5 blocks before realizing she forgot her math book at school and would need it for her homework. Sh

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B shows her getting closer to home, immediately turning round, gives time for finding book then riding all the way home at a constant speed

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3 years ago

Read 2 more answers

What is the range of the function y=3/x+8?

myrzilka [38]

The domain of the function is (-∞, -8) and (-8, ∞). Then the range of the function will be (-∞, 0) and (0, ∞).

<h3>What are domain and range?</h3>

The domain means all the possible values of the x and the range means all the possible values of the y.

The function is given below.

y = 3/(x + 8)

Then the domain of the function is (-∞, -8) and (-8, ∞). Then the range of the function will be (-∞, 0) and (0, ∞).

More about the domain and range link is given below.

brainly.com/question/12208715

#SPJ1

3 0

2 years ago

In a G.P the difference between the 1st and 5th term is 150, and the difference between the

liubo4ka [24]

Answer:

Either $\displaystyle \frac{-1522}{\sqrt{41}}$ (approximately $-238$ ) or $\displaystyle \frac{1522}{\sqrt{41}}$ (approximately $238$ .)

Step-by-step explanation:

Let $a$ denote the first term of this geometric series, and let $r$ denote the common ratio of this geometric series.

The first five terms of this series would be:

$a$ ,
$a\cdot r$ ,
$a \cdot r^2$ ,
$a \cdot r^3$ ,
$a \cdot r^4$ .

First equation:

$a\, r^4 - a = 150$ .

Second equation:

$a\, r^3 - a\, r = 48$ .

Rewrite and simplify the first equation.

$\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}$ .

Therefore, the first equation becomes:

$a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150$ ..

Similarly, rewrite and simplify the second equation:

$\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}$ .

Therefore, the second equation becomes:

$a\, r\, \left(r^2 - 1\right) = 48$ .

Take the quotient between these two equations:

$\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}$ .

Simplify and solve for $r$ :

$\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}$ .

$8\, r^2 - 25\, r + 8 = 0$ .

Either $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ or $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ .

Assume that $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}$ .

Similarly, assume that $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = \frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}$ .

4 0

3 years ago