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2 years ago

What is x more than 3x-1

Mathematics

1 answer:

Fofino [41]2 years ago

5 0

Answer:

Step-by-step explanation:

3x - 1 +x = 2x-1

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The residents of a city voted on whether to raise property taxes. The ratio of yes votes to no votes was 5 to 3 . If there were

Alchen [17]

Answer:

There were 2747 yes votes.

Step-by-step explanation:

This question can be solved using proportions.

The ratio of yes votes to no votes was 5 to 3 .

This means that for each 5 + 3 = 8 votes, 5 were yes and 3 were no.

If there were 4395 total votes, how many yes votes were there?

For each 8 votes, we have 5 yes. How many yes votes were there in 4395 votes?

5 yes - 8 votes

x yes - 4395 votes

8x = 4395*5

x = 4395*5/8

x = 2747

There were 2747 yes votes.

7 0

3 years ago

For the entire scatter plot is the association between the year and the distance jumped linear or nonlinear

MA_775_DIABLO [31]

your stupid........................................................................

6 0

3 years ago

Find the surface area of the cylinder.

Novosadov [1.4K]

I hope this helps you

4 0

2 years ago

Given the following right triangle, find cose, sine, tane sececsce, and cote. Do not

IgorLugansk [536]

Step-by-step explanation:

Use the Pythagorean theorem:

$leg^2+leg^2=hypotenuse^2$

We have

$leg=4,\ hypotenuse=10$

Substitute:

$4^2+leg^2=10^2$

$16+leg^2=100$ <em>subtract 16 from both sides</em>

$leg^2=84\to leg=\sqrt{84}\\\\leg=\sqrt{(4)(21)}\\\\leg=\sqrt4\cdot\sqrt{21}\\\\leg=2\sqrt{21}$

$sine=\dfrac{opposite}{hypotenuse}\\\\cosine=\dfrac{adjacent}{hypotenuse}\\\\tangent=\dfrac{opposite}{adjacent}\\\\cotangent=\dfrac{adjacent}{opposite}\\\\secant=\dfrac{hypotenuse}{adjacent}\\\\cosecant=\dfrac{hypotenuse}{opposite}$

Substitute:

$hypotenuse=10,\ opposite=4,\ adjacent=2\sqrt{21}$

$\sin\theta=\dfrac{4}{10}=\dfrac{2}{5}\\\\\cos\theta=\dfrac{2\sqrt{21}}{10}=\dfrac{\sqrt{21}}{5}\\\\\tan\theta=\dfrac{4}{2\sqrt{21}}=\dfrac{2}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{2\sqrt{21}}{21}\\\\\cot\theta=\dfrac{2\sqrt{21}}{4}=\dfrac{\sqrt{21}}{2}\\\\\sec\theta=\dfrac{10}{2\sqrt{21}}=\dfrac{5}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{5\sqrt{21}}{21}\\\\\csc\theta=\dfrac{10}{4}=\dfrac{5}{2}$

5 0

3 years ago

How many solutions are there in the equation below 8x+11=8x+8

olga_2 [115]

That is a no solution set, you have been bamboozled!

6 0

3 years ago