How is the product of 2 and 5 shown on a number line?
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You want to isolate the x-term from the constant term, so you can subtract x/3 and add 10. This gives you
... 4/9x -10 -x/3 +10 > x/3 -12 -x/3 +10
... 1/9x > -2 . . . . . . collect terms
Now, you can multiply by 9 to see the condition on x.
... 9(1/9x) > -2(9)
... x > -18
On the x-y plane, the graph of this will be a dashed line at x=-18, and the half-plane to the right of that line will be shaded.
On a number line, there will be an open circle at x=-18, and the number line to the right of that circle will be marked (bold, colored, shaded, whatever).
The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7
<em><u>Solution:</u></em>
Let "c" be the cost of 1 chocolate cake
Let "v" be the cost of 1 vanilla cake
<em><u>Jenny sold 14 chocolate cakes and 5 vanilla cakes for 119 dollars</u></em>
Therefore, we can frame a equation as:
14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119
14c + 5v = 119 ------- eqn 1
<em><u>Natalie sold 10 chocolate cakes and 10 vanilla cakes for 130 dollars</u></em>
Therefore, we can frame a equation as:
10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130
10c + 10v = 130 -------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
Multiply eqn 1 by 2
28c + 10v = 238 ------ eqn 3
<em><u>Subtract eqn 2 from eqn 3</u></em>
28c + 10v = 238
10c + 10v = 130
( - ) --------------------------
18c = 108
c = 6
<em><u>Substitute c = 6 in eqn 1</u></em>
14(6) + 5v = 119
84 + 5v = 119
5v = 119 - 84
5v = 35
v = 7
Thus cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7