Joe earned $2,400 this year. last year he earned $1,800. this year's earning were percentage of last year's.

Consider the equation below.

Korvikt [17]

Answer:

Equation in square form:

$y=3(x+5)^2-4$

Extreme value:

$(h,k)=(-5,-4)$

Step-by-step explanation:

We are given

$y=3x^2+30x+71$

we can complete square

$y=3(x^2+10x)+71$

we can use formula

$a^2+2ab+b^2=(a+b)^2$

$y=3(x^2+2\times x\times 5)+71$

now, we can add and subtract 5^2

$y=3(x^2+2\times x\times 5+5^2-5^2)+71$

$y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71$

$y=3(x+5)^2-75+71$

So, we get equation as

$y=3(x+5)^2-4$

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

$y=a(x-h)^2+k$

where

vertex=(h,k)

now, we can compare and find h and k

$y=3(x+5)^2-4$

we get

h=-5

k=-4

so, extreme value of this equation is

$(h,k)=(-5,-4)$

6 0

3 years ago

Read 2 more answers

$7000 is compounded semiannually at a rate of 11% for 21years Find the total amount and round to the nearest cent

photoshop1234 [79]

$\text{Given that }\$7000 \text{ is compounded semiannualy at a rate of }11\% \text{ for 21 years}\\
\\
\text{we know that the amount after t year when compounded is given by}\\
\\
A=P\left ( 1+\frac{r}{n} \right )^{nt}\\
\\
\text{here P is the principal amoount, so }P=7000,\\
\\
\text{r is the interest rate, }r=11\%=0.11\\
\\
\text{n is the number of times in a year, here semiannulay, so }n=2,\\
\\
\text{and t is the time, so }t=21\\
\\
\text{so the amount after 21 years is}$

$A=7000\left ( 1+\frac{0.11}{2} \right )^{2(21)}\\
\\
\Rightarrow A=7000\left ( 1+0.055 \right )^{42}\\
\\
\Rightarrow A=7000\left ( 1.055 \right )^{42}\\
\\
\Rightarrow A\approx 66328.68$

So the amount after 21 years is: $66328.68

7 0

3 years ago

A prism is completely filled with 3996 cubes that have edge lengths of 13 in.

irina [24]

The answer is 148, what grade are you in that’s really easy unless you didn’t pay attention. , anyways keep up

4 0

2 years ago

Read 2 more answers

A breakfast cereal producer makes its most popular product by combining just raisins and flakes in each box of cereal. The amoun

yarga [219]

Using the normal distribution, it is found that there is a 0.9192 = 91.92% probability that the total amount of product is less than 575 g.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

When two normal variables are added, the mean is the sum of the means while the standard deviation is the square root of the sum of the variances.

In this problem, the product is composed by flakes and raisins, and we have that:

$\mu_F = 370, \sigma_F = 24, \mu_R = 170, \sigma_R = 7$

Hence, the distribution for the total amount of product has <u>mean and standard deviation</u> given by:

$\mu = \mu_F + \mu_R = 370 + 170 = 540$

$\sigma = \sqrt{\sigma_F^2 + \sigma_R^2} = \sqrt{24^2 + 7^2} = 25$

The probability that the total amount of product is less than 575 g is the <u>p-value of Z when X = 575</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{575 - 540}{25}$

$Z = 1.4$

$Z = 1.4$ has a p-value of 0.9192.

0.9192 = 91.92% probability that the total amount of product is less than 575 g.

A similar problem is given at brainly.com/question/22934264

5 0

2 years ago

12 cos theta minus 16 sin theta is equal to zero find 2 sin theta + cos theta

gayaneshka [121]

Answer:

2sinθ + cosθ = 2

Step-by-step explanation:

12 cos θ - 16 sinθ = 0

=> 3 cos θ -4 sin θ = 0

=> tanθ = 3/4

let P = 3x

B = 4x

=> H= 5x

=> sinθ = P/H = 3/5

cosθ = B/H = 4/5

2sinθ + cosθ

= 2× 3/5 + 4/5

= 6/5+4/5

= 10/5

= 2

=> 2sinθ + cosθ = 2

5 0

3 years ago

Read 2 more answers

Joe earned $2,400 this year. last year he earned $1,800. this year's earning were percentage of last year's.​

Joe earned $2,400 this year. last year he earned $1,800. this year's earning were percentage of last year's.