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Katena32 [7]
3 years ago
8

Your neighbor leaves his yard, which is 120 ft from the bus stop. He begins to walk toward you at the bus stop and then passes y

ou. He walks at a speed of 4 ft/s. His distance d from you after t seconds is given by d = |120 − 4t|. After how many seconds is your neighbor 30 ft from you?
Mathematics
1 answer:
Sergio [31]3 years ago
5 0

Answer:

any fraction's? I can't tell

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Sumi rides at a constant speed of 10 ft/s. Write an equation that expresses the distance d that sumi has traveled as a function
Shtirlitz [24]

Answer:

d = 10s

Step-by-step explanation:

The formula for calculating the speed of Sumi is expressed as;

Speed = distance/time

Given

Speed = 10ft/s

time = s seconds

Required

Distance travelled as a function of time;

from the formula;

Distance = Speed * time

Distance = 10 * s

d = 10s

Hence the equation that expresses the distance d that sumi has traveled as a function of the time s in seconds since she started riding her bike is;

d = 10s

3 0
3 years ago
Little Melinda has nickels and quarters in her bank. She has two
SCORPION-xisa [38]

A) N +2 = Q which equals

A) N -Q = -2

B) .05N +.25Q = 3.50  multiplying A) by .25

A) .25N -.25Q = -.5  then adding A) and B)

.30N = 3

Nickels = 10 Quarters = 12

*************DOUBLE CHECK ***************

.05 nickels = $0.50  .25 Quarters = $3.00





7 0
3 years ago
Пожалуйста,очень нужны 4,5,6<br> Срочнооооооо<br> Спасибо заранее
kifflom [539]
B. is the answer to your question!! Hope this helps!! :D
4 0
4 years ago
Question 12<br> With steps please
34kurt

Answer:\ \boxed{5^2}

\sqrt[n]{a}=a^\frac{1}{n}\\\\\text{therefore}\\\\\sqrt5=5^\frac{1}{2}\\----------------\\25=5^2\\----------------\\78,125=5^7\\----------------\\\text{use}\\\\a^n\cdot a^m=a^{n+m}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\----------------\\\\\dfrac{\sqrt5\times78,125}{25\times5^{\frac{7}{2}}}=\dfrac{5^\frac{1}{2}\times5^7}{5^2\times5^\frac{7}{2}}=\dfrac{5^{\frac{1}{2}+7}}{5^{2+3\frac{1}{2}}}=\dfrac{5^{7\frac{1}{2}}}{5^{5\frac{1}{2}}}=5^{7\frac{1}{2}-5\frac{1}{2}}=\boxed{5^2}

6 0
3 years ago
2. Two angles have a common vertex but no common side. How can you tell whether the angles are vertical angles?
Maksim231197 [3]

Explanation:

The angles are <em>vertical angles</em> if the opposites of the rays forming one of the angles are the rays forming the other angle.

More formally, if V is the common vertex, and ...

  • R is a point on one of the rays forming Angle 1
  • S is a point on the ray that is the opposite of ray VR
  • T is a point on the other ray forming Angle 1
  • U is a point on the ray that is the opposite of ray VT

Then angle RVT and angle SVU are vertical angles.

___

Another way to say this is that points R, V, S are collinear, as are points T, V, U, and the two angles of interest are RVT and SVU.

If the above conditions cannot be met, then the angles are not vertical angles.

7 0
3 years ago
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