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prisoha [69]
3 years ago
6

BRAINLIEST ANSWER TO ANYONE WHO HELPS ME FIND QUESTIONS 1,2 AND 3

Mathematics
1 answer:
Vladimir [108]3 years ago
6 0
1. a)CK²=CH²+HK²,  CH - radius
CH²=CK²-HK²=50²-30²=2500-900=1600 ft²
CH=40 ft  -- radius
b) cos(KCH)= CH/CK=40/50=4/5
KCH=arccos(4/5)≈36.87°
2)C=2πr≈2*3.14*40=251.2 ft
C=2*40π=80π ft --- exact
3) A =πr²=40²π=1600π ----exact
A≈1600*3.14=5024 ft
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Using it's concepts, it is found that for the function f(x) = \frac{5x}{x - 25}:

  • The vertical asymptote of the function is x = 25.
  • The horizontal asymptote is y = 5. Hence the end behavior is that y \rightarrow 5 when x \rightarrow \infty.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity. They also give the end behavior of a function.

In this problem, the function is:

f(x) = \frac{5x}{x - 25}

For the vertical asymptote, it is given by:

x - 25 = 0 -> x = 25.

The horizontal asymptote is given by:

y = \lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{5x}{x - 25} = \lim_{x \rightarrow \infty} \frac{5x}{x} = 5

More can be learned about asymptotes at brainly.com/question/16948935

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<span>So the area of the park, excluding the fountain, is </span>
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