<span>The answer is A. p2 = 0.36, 2pq = 0.48, q2 = 0.16.</span>
<span>
</span><span>
Let's first distinguish alleles frequencies from
genotypes frequencies:
p - a frequency of R allele,
q - a frequency of r allele,
p² - a frequency of RR genotype,
2pq - a frequency of Rr genotype,
q² - a frequency of rr genotype.</span>
<span>
<span>The gene frequency of allele r changes from 0.38
to 0.40, thus:
q = 0.40</span>
Now, we will implement this in the following
equation:
p + q = 1
If q = 0.40, then:
p + 0.40 = 1
</span>⇒ p = 1 - 0.40<span>
</span>⇒ p = 0.60
<span>
<span>Now, the frequencies of both alleles are know
and it is easy to calculate the genotype frequencies:
- the frequency of RR genotype: p² = 0.60² = 0.36</span>
- the frequency of Rr genotype: 2pq =
2 · 0.60 · 0.40 = 0.48
- the frequency of rr genotype: q² = 0.40² =
0.16</span>
<span>
<span>Therefore, the new genotype frequencies in
that population are p2 = 0.36, 2pq = 0.48, q2 = 0.16.</span></span>
<h2>Performance of jaw-thrust maneuver</h2>
Explanation:
- The medical emergency services provide medical facilities to individuals. The service can be provided in case of accidents, sudden injury, heart attack, and other medical situations.
- The individual should provide the emergency first aid that prevents the individual tongue from the obstruction of his upper airways. The maneuver is mainly performed on the supine patient. This first aid provides the proper oxygen in the patient's body.
- The occluded teeth typically forestall progress ahead of the mandible, and the thumbs must discourage the mentum while the fingers hold mandible and lift it upward. This results in the mandibular teeth projecting before the maxillary teeth (after the mouth opens slightly)
Where are the "following structures"?
