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3 years ago

Evaluate the expression below, if a = 3, b = 4, c = 12, and d = 1

Mathematics

1 answer:

Maksim231197 [3]3 years ago

4 0

Alabama hi hi hi hi hi hi hi hi hi hi

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When 1,250^3/4 is written in simplest radical form, which value remains under the radical?

ddd [48]

Answer:

2 is inside the radical.

Step-by-step explanation:

We have to write the radical expression $1250^{3/4}$ in simplest form

Let us find the factors of 1250

$1250 = 2\times5^4$

Hence, we can rewrite the radical expression as

$(2\times5^4)^{3/4}$

Using the exponent rule $(x^a)^b=x^{ab}$

$(2^{3/4})\times(5^{4\cdot3/4})\\\\=2^{3/4}\times125$

Hence, we have 2 is inside the radical.

5 0

3 years ago

Read 2 more answers

PLEASE HELP ME WITH THIS!!

gregori [183]

The last one is the answer. GD is similar to MJ, and DE is similar to JK. While DE is similar to ML as well, it is more so to JK because they are facing the same way

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4 years ago

What is the value of x? 56 28 33 47

jeyben [28]

28 probably not right

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3 years ago

Find the derivatives of the following implicit function

ddd [48]

Answer:

$\frac{d}{dx}\left(y\right)=\frac{2-6x+6y}{-6x+2y+1}$

Step-by-step explanation:

$3x^2-6xy+y^2=2x-y\\\mathrm{Treat\:}y\mathrm{\:as\:}y\left(x\right)\\\mathrm{Differentiate\:both\:sides\:of\:the\:equation\:with\:respect\:to\:}x\\\frac{d}{dx}\left(3x^2-6xy+y^2\right)=\frac{d}{dx}\left(2x-y\right)\\\frac{d}{dx}\left(3x^2-6xy+y^2\right)=6x-6\left(y+x\frac{d}{dx}\left(y\right)\right)+2y\frac{d}{dx}\left(y\right)\\\frac{d}{dx}\left(2x-y\right)=2-\frac{d}{dx}\left(y\right)\\6x-6\left(y+x\frac{d}{dx}\left(y\right)\right)+2y\frac{d}{dx}\left(y\right)=2-\frac{d}{dx}\left(y\right)$

$\mathrm{For\:convenience,\:write\:}\frac{d}{dx}\left(y\right)\mathrm{\:as\:}y^{'\:}\\6x-6\left(y+xy^{'\:}\right)+2yy^{'\:}=2-y^{'\:}\\\mathrm{Isolate}\:y^{'\:}:\quad y^{'\:}=\frac{2-6x+6y}{-6x+2y+1}\\y^{'\:}=\frac{2-6x+6y}{-6x+2y+1}\\\mathrm{Write}\:y^{'\:}\:\mathrm{as}\:\frac{d}{dx}\left(y\right)\\\frac{d}{dx}\left(y\right)=\frac{2-6x+6y}{-6x+2y+1}$

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3 years ago

Eight angles of a nonagon measure 1389, 154º. 145°, 132°, 148°, 143,

PIT_PIT [208]

Answer:

103°

Step-by-step explanation:

The total angle in a nonagon is 1260. To get the missing angle, we add up all the given angle together and subtract it from 1260.

138 + 154º + 145° + 132° + 148° + 143 + 147 + 150 = 1157

1260 - 1157 = 103

Therefore, the missing angle is 103°

6 0

3 years ago