Considering the given table, we have that:
- The function has a relative maximum when x is near 3.
- As x approaches positive infinity, the value of the function approaches negative infinity.
<h3>When a function has a relative maximum?</h3>
A function has a relative maximum when it changes from increasing to decreasing.
Looking at the given table, it happens when x is near 3.
Also, looking at the table, for x > 3 the function is decreasing, hence as x approaches positive infinity, the value of the function approaches negative infinity.
More can be learned about functions at brainly.com/question/24737967
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Answer:
Since it has smaller absolute and relative errors, 355/113 is a better aproximation for
than 22/7
Step-by-step explanation:
The formula for the absolute error is:
Absolute error = |Actual Value - Measured Value|
The formula for the relative error is:
Relative error = |Absolute error/Actual value|
I am going to consider the actual value of
as 3.14159265359.
In the case of 22/7:
22/7 = 3.14285714286.
Absolute error = |3.14159265359 - 3.14285714286| = 0.00126448927
Relative error = 0.00126448927/3.14159265359 = 0.00040249943 = 0.04%
In the case of 355/113
355/113 = 3.14159292035
Absolute error = |3.14159265359 - 3.14159292035| = 0.00000026676
Relative error = 0.00000026676/3.14159265359 = 0.000000085 = 0.0000085%
Since it has smaller absolute and relative errors, 355/113 is a better aproximation for
than 22/7
245, if x represents the number of minutes then you use 5 where x would be in the function so 49(5) which is 245 jumping jacks in 5 minutes.
Answer:
Hi there!
Your answer is:
n= 2/h - q^3
q= ![\sqrt[3]{\frac{2}{h}-n }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B2%7D%7Bh%7D-n%20%7D)
h= 2 / (n+q^3)
Step-by-step explanation:
2=(n+q^3)h
/h
2/h = (n+ q^3)
-q^3
2/h-q^3 = n
2=(n+q^3)h
/h
2/h = n+q^3
-n
2/h - n= q^3
= q
2= (n+q^3)h
/n+q^3
2 / (n+q^3) = h
Hope this helps and that edge is going well :D
Signed,
A fellow Edge Student ;)
Answer:
does not exist
Step-by-step explanation:
