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AURORKA [14]
3 years ago
5

Solve the rational equation 2x^2 + 1/x-1 + x = 3 + 3/x -1 A. X= 1/3, x= 1 B. X=1/3 C. X=1 D. There is no solution

Mathematics
2 answers:
serious [3.7K]3 years ago
7 0

Answer:

There is no solution

Step-by-step explanation:

Given the rational equation 2x^2 + 1/x-1 + x = 3 + 3/x -1

We are to find the value of x

Collect like terms

2x²+x-3 = 3/x-1 - 1/x-1

2x²+x-3 = 2/x-1

Cross multiply

(2x²+x-3) (x-1) = 2

2x³-2x²+x²-x-3x+3-2 = 0

2x³-x²-4x+1 = 0

Since we cannot factor the polynomial, hence there is no solution

Pachacha [2.7K]3 years ago
3 0

Answer:

1/3

Step-by-step explanation:

a p e x

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For the answer to the question above, 
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8 0
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Could someone please help me with this? Solution set of lx^2+mx+n=0 is...?
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Answer:

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Add '-1mx' to each side of the equation.

lx2 + mx + -1mx + n = 0 + -1mx

Combine like terms: mx + -1mx = 0

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Remove the zero:

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Add '-1n' to each side of the equation.

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Step-by-step explanation:

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