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Rudik [331]
2 years ago
10

Solve the proportion (last was wrong, i apologize to those who answered my previous one!!)

Mathematics
2 answers:
natta225 [31]2 years ago
6 0

Answer:

x=±√(-66)

(there is no real solution)

Step-by-step explanation:

iVinArrow [24]2 years ago
3 0

Answer:

hngbkx8uff

jrgjgk

Step-by-step explanation:

jgjk

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decide which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring. −b b2 − 4ac 2a u
Romashka [77]

Answer:

Step-by-step explanation:

A quadratic equation can be factorised if and only if there are rational roots.

For any quadratic equation the discriminant decides about the nature of roots.

Thus only if the discriminant is a perfect square we can have rational roots and in this case only factorization is possible.

In the given equation

2x^2+ 7x+ 3 = 0\\a=2, b=7, c=3\\b^2-4ac = 1

Since 1 is a perfect square we can factor and solve

2x^2 +7x +3 = 0\\(2x+1)(x+3)=0\\x=-1/2 or x = -3

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2 years ago
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Please give the answer.<br>what is 44x65<br>​
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44x65=2860 is the answer
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3 years ago
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Which of these relations are functions ?
Alex17521 [72]
Your answer is 3. Y=2x-5
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X =<br><br> 12<br> 9<br> 6 2/3<br> help me out please you guys are awesome ^-^
vitfil [10]

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4 0
2 years ago
You are at a stall at a fair where you have to throw a ball at a target. There are two versions of the game. In the first
Tomtit [17]

Answer:

P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729

And the probability of loss with the first wersion is 0.729

P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Alternative 1

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=3, p=0.1)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We can find the probability of loss like this P(X=0) and if we find this probability we got this:

P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729

And the probability of loss with the first wersion is 0.729

Alternative 2

Let Y the random variable of interest, on this case we now that:

Y \sim Binom(n=5, p=0.05)

The probability mass function for the Binomial distribution is given as:

P(Y)=(nCy)(p)^y (1-p)^{n-y}

Where (nCx) means combinatory and it's given by this formula:

nCy=\frac{n!}{(n-y)! y!}

We can find the probability of loss like this P(Y=0) and if we find this probability we got this:

P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

4 0
3 years ago
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