If you are charging 5 per hour use h to determine how many hours and add 10 for the connection fee
5h+10
we know that
For the function shown on the graph
The domain is the interval--------> (-∞,0]

All real numbers less than or equal to zero
The range is the interval--------> [0,∞)

All real numbers greater than or equal to zero
so
Statements
<u>case A)</u> The range of the graph is all real numbers less than or equal to 
The statement is False
Because the range is all numbers greater than or equal to zero
<u>case B)</u> The domain of the graph is all real numbers less than or equal to 
The statement is True
See the procedure
<u>case C)</u> The domain and range of the graph are the same
The statement is False
Because the domain is all real numbers less than or equal to zero and the range is is all numbers greater than or equal to zero
<u>case D)</u> The range of the graph is all real numbers
The statement is False
Because the range is all numbers greater than or equal to zero
therefore
<u>the answer is</u>
The domain of the graph is all real numbers less than or equal to 
Answer:
2/y^5
Step-by-step explanation:
not sure but i think its this
Answer:
A = 222 units^2
Step-by-step explanation:
To find the area of this trapezoid, first draw an imaginary horizontal line parallel to AD and connecting C with AB (Call this point E). Below this line we have the triangle CEB with hypotenuse 13 units and vertical side (21 - 16) units, or 5 units. Then the width of the entire figure shown can be obtainied using the Pythagorean Theorem:
(5 units)^2 + CE^2 = (13 units)^2, or 25 + CE^2 = 169. Solving this for CE, we get |CE| = 12.
The area of this trapezoid is
A = (average vertical length)(width), which here is:
(21 + 16) units
A = --------------------- * (12 units), which simplifies to:
2
A = (37/2 units)(12 units) = A = 37*6 units = A = 222 units^2
ES is half of EF since a chord is bisected by the radius. ES = 10